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EastWind [94]
3 years ago
6

What point divides the line segment between (10,-2) and (-6,6) into a ratio of 5:3

Mathematics
1 answer:
olganol [36]3 years ago
3 0

Answer: (0,3)

Step-by-step explanation:

You follow the formulas to find the x and y of the dividing points.

Xp= x1+ a/a+b (x2-x1)

Xp= 10+5/5+3(-6-10)

Xp=10+5/8(-16)

Solve the problem above and you end up with “0” as your x.

Yp= y1+ a/a+b (y2-y1)

Yp= -2+ 5/8 (6+2)

Yp= -2+ 5/8 (8)

Solve this problem above and you end up with “3” as your y. Therefore, the point that divides the line segment between (10, -2) and (-6,6) into a ratio of 5:3 is (0, 3).

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vichka [17]

Answer:

The answer to your question is the third option

Step-by-step explanation:

To know if two lines are parallel we must get their slopes if the slopes are equal, the lines are parallel.

Data

A (2,2)

B (3,6)

C(0,5)

D(1,9)

Formula

slope = \frac{y2 - y1}{x2 - x1}

Process

1.- Calculate the slope of line 1

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slope 1 = \frac{4}{1}

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