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2 years ago

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14. Janie Christopher lent $6000 to a friend for 90 days at 12%. After 30 days, she sold the note to a third party for $6000. Wh

at annual simple interest rate did the third party receive? Use 360 days in a year

1 answer:

Elenna [48]2 years ago

3 0

Can you do plsssssssss

help me plssssssssssss meee

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a room contains 156.1m of air . if the room is 8.31m long and 5.72m wide . use tabe to calculate it height

irga5000 [103]

Answer:

height=3.28m

Step-by-step explanation:

air means volume of room

let the height of room be x.

so, volume of room= 156.1 m³

8.31*5.72*x=156.1m³

x =3.28m

8 0

3 years ago

Find the slope and the y intercept of a line that passes through these points (2,2)and (3,0)

34kurt

Answer:

That's the slope

Step-by-step explanation:

(2,2( and (3,0)

<u>0-2 </u>=<u> -2 </u>

3-1 = 2

= -1

8 0

3 years ago

The scores of individual students on the American College Testing (ACT) Program College Entrance Exam have a normal distribution

tekilochka [14]

Answer:

The probability that the average of the scores of all 400 students exceeds 19.0 is larger than the probability that a single student has a score exceeding 19.0

Step-by-step explanation:

Xi~N(18.6, 6.0), n=400, Yi~Ber(p); Z~N(0, 1);

$P(0\leq X\leq 19.0)=P(\frac{0-\mu}{\sigma} \leq \frac{X-\mu}{\sigma}\leq \frac{19-\mu}{\sigma}), Z= \frac{X-\mu}{\sigma}, \mu=18.6, \sigma=6.0$

$P(-3.1\leq Z\leq 0.0667)=\Phi(0.0667)-\Phi (-3.1)=\Phi(0.0667)-(1-\Phi (3.1))=0.52790+0.99903-1=0.52693$

P(Xi≥19.0)=0.473

$\{Yi=0, Xi< 19\\Yi=1, Xi\geq 19\}$

p=0.473

Yi~Ber(0.473)

$P(\frac{1}{n}\displaystyle\sum_{i=1}^{n}X_i\geq 19)=P(\displaystyle\sum_{i=1}^{400}X_i\geq 7600)$

Based on the Central Limit Theorem:

$\displaystyle\sum_{i=1}^{n}X_i\~{}N(n\mu, \sqrt{n}\sigma),\displaystyle\sum_{i=1}^{400}X_i\~{}N(7440, 372)$

Then:

$P(\displaystyle\sum_{i=1}^{400}X_i\geq 7600)=1-P(0$

$P(\displaystyle\sum_{i=1}^{n}Y_i=1)=P(\displaystyle\sum_{i=1}^{400}Y_i=1)$

Based on the Central Limit Theorem:

$\displaystyle\sum_{i=1}^{400}Y_i\~{}N(400\times 0.473, \sqrt{400}\times 0.499)=\displaystyle\sum_{i=1}^{400}Y_i\~{}N(189.2; 9.98)$

$P(\displaystyle\sum_{i=1}^{400}Y_i=1)\~{=}P(0.5$

Then:

the probability that the average of the scores of all 400 students exceeds 19.0 is larger than the probability that a single student has a score exceeding 19.0

7 0

3 years ago

Please answer! 10 points!

aivan3 [116]

Answer:

its nine degrees

Step-by-step explanation:

this is also 5 pts btw

3 0

2 years ago

Emeka and Maricel were asked to find an explicit formula for the sequence 79,71,63,55, Emeka said the formula is h(n)=79-8(n-1)

choli [55]

Answer:

Actually the same

Step-by-step explanation:

Emekas formula : h(n)=79-8(n-1)

h(n)=79-8n+8

The result of Emekas formula : h(n)=87-8n (Maricels Formula)

7 0

3 years ago

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