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3 years ago

Please help I’ll mark you as brainliest if correct!

Mathematics

1 answer:

romanna [79]3 years ago

4 0

Answer:

The wright answer is 16.33 inches

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What is the exact distance from (-5,1) to (3,0).

Ilya [14]

Answer:

The distance between the two points is $\sqrt{65} \ \text{units}.$

Step-by-step explanation:

In order to find the distance between two coordinate pairs, we can use the distance formula:

$\displaystyle \bullet \ \ \ d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Our coordinate pairs need to be labeled accordingly, so we can use this naming system:

$\bullet \ \ \ (x_1, y_1), (x_2, y_2)$

This assigns a name to our points:

$x_1 = -5$
$y_1 = 1$
$x_2 = 3$
$y_2 = 0$

Therefore, we can plug these into the formula and solve:

$d=\sqrt{(3-(-5))^2+(0-1)^2}\\\\d=\sqrt{(8)^2+(-1)^2}\\\\d=\sqrt{8^2+1^2}\\\\d=\sqrt{64+1}\\\\d=\sqrt{65}$

Therefore, the distance between the two points is $\sqrt{65} \ \text{units}$ .

5 0

3 years ago

Help !! Multiply: 2w(w+17)

kotykmax [81]

Answer:

2w^2 + 34w

Step-by-step explanation:

2w(w+17)

Multiply the 2w by each term in the parentheses

2w*w + 2w*17

2w^2 + 34w

6 0

3 years ago

Which option below best describes the polynomial 10x^3 ?

MAXImum [283]

The answer is C, there’s only 1 term= monomial

5 0

3 years ago

Write an equation for a parabola in which the set of all points in the plane are equidistant from the focus and line F(-6,0); x=

Bogdan [553]

Step-by-step explanation:

Since we have a vertical directrix, the equation of the parabola is

$(y - k) {}^{2} = 4p(x - h)$

Where p is the distance from the vertex to the directrix.

or the distance from the vertex to the focus.

Since we have a sideways parabola, let use the point for the directrix is (-6,0). So let find the midpoint of (-6,0) and (6,0). That would be our vertex.

$\frac{ - 6 + 6)}{2} = 0$

$\frac{0 + 0}{2} = 0$

So our vertex is (0,0).

So our equation become

${y}^{2} = 4px$

The distance from the focus and directrix is 6.

So p=6.

${y}^{2} = 24x$

So p is 6.

Since p is 6,

$\frac{ {y}^{2} }{24} = x$

3 0

2 years ago

What is universal gravitational constant

koban [17]

Answer:

6.67408 × 10^-11 m^3 kg^-1 s^-2

Step-by-step explanation:

F = G M 1 M 2 d 2 , where F is the gravitational force between two point masses, M1 and M2; d is the distance between M1 and M2; G is the universal gravitational constant, usually taken as 6.670 × 1011 m3/(kg)(s2) or 6.670 × 10−8 in centimeter–gram–second units. a = F M 1 = G M 2 r 2 .

8 0

3 years ago