Answer: There are 24336000 different codes that are possible.
Step-by-step explanation:
We know that,
Total alphabets = 26
Total digits = 10
Choices for First place = 26+10=36
Choices for next 3 places = 10 x 10 x 10 = 1000
Choices for last 2 places = 26 x 26 = 676
Total different codes are possible = 36 x 1000 x 676
=24336000
Hence, there are 24336000 different codes that are possible.
The answer is [(10,000*y^16)/t^16]. At first, you have to distribute the exponent -4 to the numerator and denominator by virtue of the law of exponent, (a/b)^n = [(a^n)/(b^n)]. After distribution, you get (t^-16)/[(10^-4)*(y^-16)]. To simplify the negative exponent, follow the law of exponent: a^-m = 1/a^m. Thus, you now have [(10^4)*(y^16)]/(t^16). Hence, the answer is [(10,000*y^16)/t^16].
Answer:
x = 9
y = 12
Step-by-step explanation:
✔️m<ADB = 90°
7x + 27 = 90
7x = 90 - 27
7x = 63
Divide both sides by 7
x = 9
✔️BC = 2(BD)
3y - 7 = 2(y + 3)
3y - 7 = 2y + 6
Collect like terms
3y - 2y = 7 + 6
y = 12
5y-x=10
Isolate the variable
add x to both sides
5y-x+x=10+x
5y=10+x
Divide both sides by 5
5y/5=10+x/5
y=2+1/5x
So y is equal to 2+1/5x
Answer:
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