Answer:
The area is 28.
Step-by-step explanation:
Visualize the rectangle as 2 split squares.
The top square is easily 4x4, so the area of that part is 16.
Now visualize the bottom square as two rectangles.
To find the area of the dented side, you would use the equation of finding the area of a triangle, a=(w x h)
because the dented side is actually just one half of the rectangle on the other side.
Since it is the same height as the top square, but is 2 in width, it would be written as a=(2 x 4) . So the area of that part is 4, and the area of the other rectangle would be just 2 x 4 so it is 8.
Totaling these numbers, you get the area of the full rectangle.
3s+28=85, take away 28 from both sides of the equals to give you 3s=57, divide by 3 on both side to give you s=19.
X| 1 | 15 | 225 |
y| 4 | ? | 900 |
therefore
[tex]\dfrac{4}{1}=4;\ \dfrac{900}{225}=4;\ \dfrac{?}{15}=4\to?=60[\tex]
Answer: ? = 60
Answer:
Step-by-step explanation:
A line perpendicular to the given line has a slope that is the negative inverse of the reference line.
Rewrite the given equation in the format of y=mx+b, where mi is the slope and b is the y-intercept (the value of y when x = 0.
2x + 3y = 4
3y=-2x+4
y = -(2/3)X + (4/3)
The reference slope is -(2/3). The negative inverse is (3/2), which will be the slope of a perpendicular line. We can write the new line as:
y = (3/2)x + b
Any value of b will still result in a line that is perpendicular. But we want a value of b that will shift the line so that it intersects the point (-3,-5). Simply enter this point in the above equation and solve for b.
y = (3/2)x + b
-5 = (3/2)(-3) + b
-5 = -(9/2) + b
-5 = -4.5 + b
b = - 0.5
The equation of the line that is perpendicular to 2x + 3y = 4 and includes point (-3,-5) is
y = (3/2)x - 0.5
