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3 years ago

What is 30=8+4(z-2) step by step?

Mathematics

1 answer:

Stolb23 [73]3 years ago

7 0

30=8+4(z-2)

Distribute 4 through the parentheses

30=8+4z-8

Eliminate the opposites

30=4z

Swap the sides of the equation

4z=30

Divide both sides of the equation by 4

4z÷4=30÷4

Any expression divided by itself equals 1

z=30÷4

or write the division as a fraction

z=30/4

copy the numerator and denominator of the fraction

30=2x3x5

4=2x2

Write the prime factorization of 30

Write the prime factorization of 4

30=2 x3x5

4=2x2

Line up the common factors in both lists

Copy the common factors

Since there is only one common factor, the common factor 2 is also the greatest common factor

30÷2/4÷2

Divide 30 and 4 by the greatest common factor 2

15/4÷2

Divide the numbers in the numerator

15/2

Divide the numbers in the denominator

15/2

The simplified expression is 15/2

That's it. hope it wasn't too hard to understand?

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V = Bh, where B is the area of the circular base.
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mario62 [17]

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a square measuring 9 inches by 9 inches is cut from the corners of a square measuring 15 inches by 15 inches what is the area of

ss7ja [257]

Answer:

144 in²

Step-by-step explanation:

Find the area of the larger square, then subtract the area of the square we cut out.

The larger square has side length of 15, so it has an area of 15² = 225 in²

The smaller square has side length of 9, so it has an area of 9² = 81 in²

The area left over is

225 - 81 = 144 in²

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3 years ago

I need help with these two questions

Mandarinka [93]

Answer:

(-2,-2)

Step-by-step explanation:

for question number 15...cordinated grid shows each equation...first equation is represented by straight line going upwards through +4 in y axis...(y=3x+4)...

point is....every point in this two lines represent a possible x and y value for each equation...and there is a point where these lines meet each other....in that point...x and y values are possible values for both equations.so answer is (-2,-2)...this cordination satisfy each pairs of equation...you can try using -2 for x in both equations and get -2 as the answer for y...that proves the point..try it for 16 quiz.good luck

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3 years ago

Which of the following could NOT be the lengths of the sides of a triangle?

Furkat [3]

Given:

Sides of triangles in the options.

To find:

Which could NOT be the lengths of the sides of a triangle.

Solution:

Condition for triangle:

Sum of two smaller sides of a triangle must be greater than the longest side.

In option A,

$5+5=10>5$

Sides 5 in, 5 in, 5 in are the lengths of the sides of a triangle.

In option B,

$10+15=25>20$

Sides 10 cm, 15 cm, 20 cm are the lengths of the sides of a triangle.

In option C,

$3+4=7>5$

Sides 3 in, 4 in, 5 in are the lengths of the sides of a triangle.

In option D,

$8+5=13$

Since, the sum of two smaller sides is less than the longest side, therefore the sides 8 ft, 15 ft, 5 ft are not the lengths of the sides of a triangle.

Therefore, the correct option is D.

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2 years ago