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2 years ago

How to simplify -12 divided by 3•(-8+(-4) to the seccond power-6)+2

1 answer:

7 0

-12/3•(-8(-4)^2-6)+2 Original Equation
-12/3•(-8+16-6)+2 Simplify the (-4)^2
-12/3•(2)+2 Simplify everything inside the equation
-8+2 Using PEMDAS, you multiply -12/3•(2)
-6 You add from there

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There is 5/8 of an hour before the end of soccer practice. It takes 1/6 of an hour for the team to complete 1 full scoring drill

Makovka662 [10]

Answer:

Three full scoring drill can be completed in $\frac{5}{8}$ hrs with $\frac{1}{8}$ hrs still remaining in end of practice session.

Solution:

Given that

Time remaining before end of soccer practice in hours = $\frac{5}{8}$

Time required for 1 full scoring drill = $\frac{1}{6}$

Need to identify how many drills can be complete before practice is over.

For sake of simplicity lets make denominators of both the numbers same.

$\frac{5}{8}=\frac{5}{8} \times \frac{3}{3}=\frac{15}{24}$

$\frac{1}{6}=\frac{1}{6} \times \frac{4}{4}=\frac{4}{24}$

$\frac{4}{24}$ is time for 1 drill

Lets say $\frac{4}{24} = d$

Time remaining = $\frac{15}{24} = \frac{4 + 4 + 4+ 3}{24} = \frac{4}{24} + \frac{4}{24} + \frac{4}{24} + \frac{3}{24} = d + d +d + \frac{3}{24}$

$\frac{15}{24} = 3d + \frac{3}{24}$

3d means three drills will be completed. Fourth drill will not complete because $\frac{3}{24}$ is not sufficient to complete a drill.

Hence mathematical representation of given situation is

$\frac{5}{8} = 3d + \frac{1}{8}$

Where d is the time required to complete one drill equal to $\frac{1}{6}$ of hour.

So three full scoring drill can be completed in $\frac{5}{8}$ hrs with $\frac{1}{8}$ hrs still remaining in end of practice session.

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2 years ago