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vichka [17]
4 years ago
8

Help URGENT! I WILL MARK BRAINLIEST!!!!!!!! JUST HELP MR FIND THE ANSWER OF THE PROBLEM IN THE IMAGE ABOVE!!!!! Worth 20 points!

!!

Mathematics
1 answer:
Anni [7]4 years ago
8 0

Answer: -8n^4 + 3n^2

(The ^ is the exponent)

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A=24 and c=26<br>what does b=____<br>show work please​
Oksi-84 [34.3K]

Answer:

f jb gfbjfmnb fjb

Step-by-step explanation:

f bmf bknmf

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3 years ago
Select from the drop-down menus to correctly complete each statement. 17.2 is 17.2 units to the ____ of zero on a number line. T
Fudgin [204]
Hello!

The number line progresses from negative infinity (extreme left) to positive infinity (extreme right). Beginning at zero, the numbers increase in value as they move to the right and decrease in value as they move to the left.

With this knowledge, we can look at the number 17.2 (a positive number) and conclude that it is placed 17.2 units to the right of zero on the number line.

The opposite of 17.2 would be (-17.2). Again, looking at this number (a negative number), we can conclude that it is placed 17.2 units to the left of zero on the number line.

I hope this helps!
3 0
3 years ago
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Start at 3. create a pattern that multiplies each number by 3 stop when you have 5 numbers
Gnesinka [82]
3, 6, 9, 12, 15
I did what you asked
7 0
3 years ago
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What is the value of q?
andre [41]

Answer: here

Step-by-step explanation:riangles QST and RST are similar.  Therefore, the following is true:

q       s

--- = ----   This results in 10q=rs.

r      10

Also, since RST is a right triangle, 4^2 + s^2 = q^2.

Since QST is also a right triangle, s^2 + 10^2 = r^2.  

           4      s

Also:  ---- = -----    which leads to s^2 = 40

           s      10

Because of this, 4^2 + s^2 = q^2 becomes 16 + 40 = 56 = q^2

Then q = sqrt(56) = sqrt(4)*sqrt(14) = 2*sqrt(14) (answer)

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6 0
3 years ago
Principle = 30,000<br>Time = 4 years<br>Rate = 30<br>Then find the simple interest ?​
Nutka1998 [239]

Answer:

\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline\color{brown}{Given:}}}}}}\end{gathered}

  • {\dashrightarrow \sf{Principle = Rs.30000}}
  • {\dashrightarrow \sf {Time = 4 \: years}}
  • \dashrightarrow \sf{Rate = 30\%}
  • \begin{gathered}\end{gathered}

\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline\color{brown}{To Find:}}}}}}\end{gathered}

  • \dashrightarrow{\sf{Simple \: Interest }}

\begin{gathered}\end{gathered}

\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline\color{brown}{Using Formula:}}}}}}\end{gathered}

\dag{\underline{\boxed{\sf{ S.I = \dfrac{P \times R \times T}{100}}}}}

Where

  • \dashrightarrow{\sf{S.I = Simple \:  Interest }}
  • {\dashrightarrow{\sf{P = Principle }}}
  • {\dashrightarrow{\sf{ R = Rate }}}
  • {\dashrightarrow{\sf{T = Time}}}

\begin{gathered}\end{gathered}

\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline\color{brown}{Solution:}}}}}}\end{gathered}

{\quad {: \implies{\sf{ S.I =  \bf{\dfrac{P \times R \times T}{100}}}}}}

Substituting the values

{\quad {: \implies{\sf{ S.I =  \bf{\dfrac{30000 \times 30\times 4}{100}}}}}}

{\quad {: \implies{\sf{ S.I =  \bf{\dfrac{30000 \times 120}{100}}}}}}

{\quad {: \implies{\sf{ S.I =  \bf{\dfrac{3600000}{100}}}}}}

{\quad {: \implies{\sf{ S.I =  \bf{\cancel{\dfrac{3600000}{100}}}}}}}

{\quad {: \implies{\sf{ S.I =  \bf{Rs.36000}}}}}

{\dag{\underline{\boxed{\sf{ S.I ={Rs.36000}}}}}}

  • Henceforth,The Simple Interest is Rs.36000..

\begin{gathered}\end{gathered}

\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline\color{brown}{Learn More:}}}}}}\end{gathered}

\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered} \dag \: \underline{\bf{More \: Useful \: Formula}}\\ {\boxed{\begin{array}{cc}\dashrightarrow {\sf{Amount = Principle + Interest}} \\ \\ \dashrightarrow \sf{ P=Amount - Interest }\\ \\ \dashrightarrow \sf{ S.I = \dfrac{P \times R \times T}{100}} \\ \\ \dashrightarrow \sf{P = \dfrac{Interest \times 100 }{Time \times Rate}} \\ \\ \dashrightarrow \sf{P = \dfrac{Amount\times 100 }{100 + (Time \times Rate)}} \\ \end{array}}}\end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered}

8 0
3 years ago
Read 2 more answers
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