Answer:
49
Step-by-step explanation:
3x squared+1
x=4
But remember PEMDAS
So 4 squared which is 16
3(16)+1
3x 16= 48 +1= 49
3+c - (4+c)
pretend that there is a -1 in front of the bracket
3+c-1(4+c)
multiply the bracket by -1
(-1)(4)=-4
(-1)(c)=-c
3+c-4-c
3-4+c-c ( combine like terms)
+c-c=0
3-4=-1
-1+0=-1
Answer:
-1
The given inequality is expressed as
0 < a < 6
This means that the values of a that would satisfy the inequality are numbers between 0 and 6 but both 0 and 6 are not inclusive. This would be shown by not making solid circles at 0 and 6. The number line is shown below
Answer:
x² - 3x + 5 - [24÷(x+3)]
Step-by-step explanation:
1. Expand (x³ + 2x - 6x - 9)
= x³ - 4x - 9
2. Divide [x³ - 4x - 9 by x+3]
= x² + [(-3x^2-4x-9) ÷ (x+3)]
3. Divide [(-3x^2-4x-9) by (x+3)]
= -3x + [(5x-9) ÷ (x+3)]
x² - 3x + [(5x-9) ÷ (x+3)]
4. Divide [(5x-9) ÷ (x+3)]
= 5 + [(-24) ÷ (x+3)]
x² - 3x + 5 + [(-24) ÷ (x+3)]
= x² - 3x + 5 - [24 ÷ (x+3)]
Hi.
The first question is a direct variation — specifically y = 1.8x
In the second one (if my calculations are correct), it's not a direction variation.
Hope this helps :)
Calculations:
y = 1.8(3) = 5.4
y does not equal x, 2x, or -2x.
