Answer:it would be 2:22
Step-by-step explanation:
If there’s 25 minutes till 10 so therefore it would be 9:35 and since it’s 9:35 four hours and 51 minutes from then would be 2:22 because the minutes would add up to 82 minutes and four hours so your answers to 2:22
Answer:
13k
Step-by-step explanation:
Given: ![8k+5k](https://tex.z-dn.net/?f=8k%2B5k)
Finding the equivalent expression.
We know the rule of addition is that adding two positive integers will give positive result or sum.
Now, lets find the equivalent expression of
.
∴ ![8k+5k= 13k](https://tex.z-dn.net/?f=8k%2B5k%3D%2013k)
Hence, the required equivalent expression is 13k.
Answer:
x = 57/28
y = -95/84
z = 97/168
Step-by-step explanation:
Use the application in the next link: https://www.zweigmedia.com/RealWorld/tutorialsf1/scriptpivotold.html
Start with the expanded array:
![\left[\begin{array}{cccc}1&5&8&1\\3&2&2&5\\-2&-7&2&5\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%265%268%261%5C%5C3%262%262%265%5C%5C-2%26-7%262%265%5C%5C%5Cend%7Barray%7D%5Cright%5D)
then using the tool provided, make row operations until you find the solution:
r2 = r2-3r1
![\left[\begin{array}{cccc}1&5&8&1\\0&-13&-22&2\\-2&-7&2&5\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%265%268%261%5C%5C0%26-13%26-22%262%5C%5C-2%26-7%262%265%5C%5C%5Cend%7Barray%7D%5Cright%5D)
r3 = r3+2r1
![\left[\begin{array}{cccc}1&5&8&1\\0&-13&-22&2\\0&3&18&7\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%265%268%261%5C%5C0%26-13%26-22%262%5C%5C0%263%2618%267%5C%5C%5Cend%7Barray%7D%5Cright%5D)
r2 = r2*(-1/13)
![\left[\begin{array}{cccc}1&5&8&1\\0&1&22/13&-2/13\\0&3&18&7\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%265%268%261%5C%5C0%261%2622%2F13%26-2%2F13%5C%5C0%263%2618%267%5C%5C%5Cend%7Barray%7D%5Cright%5D)
r1 = r1- r2*5
![\left[\begin{array}{cccc}1&0&-6/13&23/13\\0&1&22/13&-2/13\\0&3&18&7\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%260%26-6%2F13%2623%2F13%5C%5C0%261%2622%2F13%26-2%2F13%5C%5C0%263%2618%267%5C%5C%5Cend%7Barray%7D%5Cright%5D)
r3 = r3+ r2*-3
![\left[\begin{array}{cccc}1&0&-6/13&23/13\\0&1&22/13&-2/13\\0&0&168/13&97/13\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%260%26-6%2F13%2623%2F13%5C%5C0%261%2622%2F13%26-2%2F13%5C%5C0%260%26168%2F13%2697%2F13%5C%5C%5Cend%7Barray%7D%5Cright%5D)
r3 = r3*13/168
![\left[\begin{array}{cccc}1&0&-6/13&23/13\\0&1&22/13&-2/13\\0&0&1&97/168\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%260%26-6%2F13%2623%2F13%5C%5C0%261%2622%2F13%26-2%2F13%5C%5C0%260%261%2697%2F168%5C%5C%5Cend%7Barray%7D%5Cright%5D)
r2 = r2- r3*22/13
![\left[\begin{array}{cccc}1&0&-6/13&23/13\\0&1&0&-95/84\\0&0&1&97/168\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%260%26-6%2F13%2623%2F13%5C%5C0%261%260%26-95%2F84%5C%5C0%260%261%2697%2F168%5C%5C%5Cend%7Barray%7D%5Cright%5D)
r2 = r2+ r3*6/13
![\left[\begin{array}{cccc}1&0&0&57/28\\0&1&0&-95/84\\0&0&1&97/168\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%260%260%2657%2F28%5C%5C0%261%260%26-95%2F84%5C%5C0%260%261%2697%2F168%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Here you have a reduced array an therefore the answers to each variable are on each row:
![\left[\begin{array}{c}x\\y\\z\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7Dx%5C%5Cy%5C%5Cz%5Cend%7Barray%7D%5Cright%5D)
Answer:
![T_{2} = 200](https://tex.z-dn.net/?f=T_%7B2%7D%20%3D%20200)
Step-by-step explanation:
Given
Geometry Progression
![T_1 = 500](https://tex.z-dn.net/?f=T_1%20%3D%20500)
![T_4 = 32](https://tex.z-dn.net/?f=T_4%20%3D%2032)
Required
Calculate the second term
First, we need to write out the formula to calculate the nth term of a GP
![T_n = ar^{n-1}](https://tex.z-dn.net/?f=T_n%20%3D%20ar%5E%7Bn-1%7D)
For first term: Tn = 500 and n = 1
![500 = ar^{1-1}](https://tex.z-dn.net/?f=500%20%3D%20ar%5E%7B1-1%7D)
![500 = ar^{0}](https://tex.z-dn.net/?f=500%20%3D%20ar%5E%7B0%7D)
![500 = a](https://tex.z-dn.net/?f=500%20%3D%20a)
![a = 500](https://tex.z-dn.net/?f=a%20%3D%20500)
For fought term: Tn = 32 and n = 4
![32 = ar^{4-1}](https://tex.z-dn.net/?f=32%20%3D%20ar%5E%7B4-1%7D)
![32 = ar^3](https://tex.z-dn.net/?f=32%20%3D%20ar%5E3)
Substitute 500 for a
![32 = 500 * r^3](https://tex.z-dn.net/?f=32%20%3D%20500%20%2A%20r%5E3)
Make r^3 the subject
![r^3 = \frac{32}{500}](https://tex.z-dn.net/?f=r%5E3%20%3D%20%5Cfrac%7B32%7D%7B500%7D)
![r^3 = 0.064](https://tex.z-dn.net/?f=r%5E3%20%3D%200.064)
Take cube roots
![\sqrt[3]{r^3} = \sqrt[3]{0.064}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Br%5E3%7D%20%3D%20%5Csqrt%5B3%5D%7B0.064%7D)
![r = \sqrt[3]{0.064}](https://tex.z-dn.net/?f=r%20%20%3D%20%5Csqrt%5B3%5D%7B0.064%7D)
![r = 0.4](https://tex.z-dn.net/?f=r%20%3D%200.4)
Using: ![T_n = ar^{n-1}](https://tex.z-dn.net/?f=T_n%20%3D%20ar%5E%7Bn-1%7D)
and ![a = 500](https://tex.z-dn.net/?f=a%20%3D%20500)
![T_{2} = 500 * 0.4^{2-1}](https://tex.z-dn.net/?f=T_%7B2%7D%20%3D%20500%20%2A%200.4%5E%7B2-1%7D)
![T_{2} = 500 * 0.4^1](https://tex.z-dn.net/?f=T_%7B2%7D%20%3D%20500%20%2A%200.4%5E1)
![T_{2} = 500 * 0.4](https://tex.z-dn.net/?f=T_%7B2%7D%20%3D%20500%20%2A%200.4)
![T_{2} = 200](https://tex.z-dn.net/?f=T_%7B2%7D%20%3D%20200)
<em>Hence, the second term is 200</em>
Answer:
B
Step-by-step explanation:
A has 2 it crosses the x axis 2x
B Has 1.
C has 2
D has none since it never touched the x axis