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nexus9112 [7]
3 years ago
12

A pipe is leaking at 1.5 cups per day. How many gallons per week is the pipe leaking?

Mathematics
1 answer:
neonofarm [45]3 years ago
4 0
1.5 cups per day...7 days per week....1.5 * 7 = 10.5 cups per week
16 cups = 1 gallon

16/1 = 10.5/x....16 cups to 1 gal = 10.5 cups to x gal
cross multiply
(16)(x) = (1)(10.5)
16x = 10.5
x = 10.5/16
x = 0.65625 rounds to 0.66 gallons per week
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x - \frac{10}{7}

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y = x + 10/7

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3 years ago
A researcher claims that the variation in the salaries of elementary school teachers is greater than the variation in the salari
guajiro [1.7K]

Answer:

a

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The alternative hypothesis is H_a :  \sigma_1 ^2 > \sigma^2_2

b

F_{critical} = 1.8608

c

F = 2.9085

d

    The decision rule is  

Reject the null hypothesis

e

There is sufficient evidence to support the researchers claim

Step-by-step explanation:

From the question we are told that

 The first sample size is  n_1 = 30

 The sample variance for elementary school is  s^2_1 = 8324

 The second sample size is  n_2 = 30

  The sample variance for the secondary school is  s^2_2 = 2862

   The significance level is  \alpha = 0.05

The null hypothesis is  H_o :  \sigma^2_1 = \sigma^2 _2

The alternative hypothesis is H_a :  \sigma_1 ^2 > \sigma^2_2

Generally from the F statistics table  the critical value of \alpha = 0.05 at first and  second degree of freedom df_1 = n_1 - 1 = 30 - 1 = 29 and  df_2 = n_2 - 1 = 30 - 1 = 29 is  

         F_{critical} = 1.8608

Generally the test statistics is mathematically represented as

       F = \frac{s_1^2 }{s_2^2}

=>   F = \frac{8324 }{2862}

=>   F = 2.9085

Generally from the value obtained we see that  F >  F_{critical } Hence

   The decision rule is  

Reject the null hypothesis

    The conclusion is  

  There is sufficient evidence to support the researchers claim

   

4 0
3 years ago
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