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nexus9112 [7]
3 years ago
12

A pipe is leaking at 1.5 cups per day. How many gallons per week is the pipe leaking?

Mathematics
1 answer:
neonofarm [45]3 years ago
4 0
1.5 cups per day...7 days per week....1.5 * 7 = 10.5 cups per week
16 cups = 1 gallon

16/1 = 10.5/x....16 cups to 1 gal = 10.5 cups to x gal
cross multiply
(16)(x) = (1)(10.5)
16x = 10.5
x = 10.5/16
x = 0.65625 rounds to 0.66 gallons per week
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\int (x+1)\sqrt(2x-1)dx
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\int (x+ 1) \sqrt{2x-1} dx =  \frac{1}{3}(x+1) (2x - 1)^{\frac{3}{2} } - \ \frac{1}{15}(2x-1)^{\frac{5}{2}} + C

Step-by-step explanation:

\int (x+1)\sqrt {(2x-1)} dx\\Integrate \ using \ integration \ by\ parts \\\\u = x + 1, v'= \sqrt{2x - 1}\\\\v'= \sqrt{2x - 1}\\\\integrate \ both \ sides \\\\\int v'= \int \sqrt{2x- 1}dx\\\\v = \int ( 2x - 1)^{\frac{1}{2} } \ dx\\\\v =  \frac{(2x - 1)^{\frac{1}{2} + 1}}{\frac{1}{2} + 1}} \times \frac{1}{2}\\\\v= \frac{(2x - 1)^{\frac{3}{2}}}{\frac{3}{2}} \times \frac{1}{2}\\\\v = \frac{2 \times (2x - 1)^{\frac{3}{2}}}{3} \times \frac{1}{2}\\\\v = \frac{(2x - 1)^{\frac{3}{2}}}{3}

\int (x+1)\sqrt(2x-1)dx\\\\   = uv - \int v du                              

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