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Semmy [17]
3 years ago
10

Need help with question please.

Mathematics
2 answers:
Nimfa-mama [501]3 years ago
8 0

m<A + m<B +m<C = 180
6x - 1 + 20 + x + 14 = 180
7x + 33 = 180
7x = 180 -33
7x = 147
x= 147/7
x= 21

m<A = 6x - 1 = 6(21) - 1 = 125
m<C = x + 14 = 21 + 14 = 35

Alex777 [14]3 years ago
4 0
(6x-1)(x+14)=160 because b is 20 and total they equal 180 so you -14 from both sides then you have 6x-1+x=146 then you add 1 to both sides and you have 7x=147 then you divide 7 from both sides and get 21=x and then you (6(21)-1) =125 =A
((21)+14) =35 =C
hope that helps

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a) P(X

P(z

b) P(X>195) =P(Z>\frac{195-183}{10.5})=P(Z>1.143)

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And using a calculator, excel ir the normal standard table we have that:

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Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Part a

Let X the random variable that represent the heights of a population, and for this case we know the distribution for X is given by:

X \sim N(183,10.5)  

Where \mu=183 and \sigma=10.5

We are interested on this probability

P(X

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X

And we can find this probability with the normal standard table or with excel:

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Part b

P(X>195)

P(X>195) =P(Z>\frac{195-183}{10.5})=P(Z>1.143)

And we can find this probability with the normal standard table or with excel: using the complement rule

P(z>1.143)=1-P(Z

Part c

P(173

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(173And we can find this probability on this way:

P(-0.953

And in order to find these probabilities we can use tables for the normal standard distribution, excel or a calculator.  

P(-0.953Part d

Since the distributiion for X is normal then the distribution for the sample mean is also normal and given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And we eant this probability:

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And using a calculator, excel ir the normal standard table we have that:

P(Z>21.08)=1-P(Z

So for this case we expect anyone with a heigth higher than 190 cm in a random sample of 1000.

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