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lukranit [14]
3 years ago
7

Which one art or sience

Business
2 answers:
Murljashka [212]3 years ago
8 0

Answer:

science....^_^^_^^_^^_^^_^^_^^_^^_^^_^

nasty-shy [4]3 years ago
6 0

Explanation:

I think art

nonono science

no arts

no science

I don't know

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What is the name for the practice whereby a married woman loses all of her political and economic rights to her husband?.
Nadya [2.5K]

<u>Coverture</u> is the name for the practice whereby a married woman loses all of her political and economic rights to her husband. Hence, the correct answer is coverture. Read below about coverture.

<h3>What is coverture?</h3>

Coverture was a legal doctrine in the English common law in which a married woman's legal existence was considered to be merged with that of her husband, so that she had no independent legal existence of her own.

Therefore, the correct answer is as given above

learn more about coverture: brainly.com/question/7413269

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5 0
1 year ago
The number of years a person that age is expected to have left to live on average is known as?
aleksley [76]
Perhaps, life expectancy...  That may be your answer.

6 0
2 years ago
Read 2 more answers
Three important forms of long-term (capital) expenditures are
Anna35 [415]

Answer:

Explanation:

Expenditure made to reduce costs; Expenditure made to increase revenue; Expenditure which is justified on non-economic grounds.

6 0
3 years ago
Suppose that a company needs new equipment, and that the machinery in question earns the company revenue at a continuous rate of
julia-pushkina [17]

Answer:

a-The present value of revenue in the first year is $61,085.92.

b-The total time it would take to pay for its price is 2.44 years of 29.33 months.

Explanation:

a-

Let the function of the revenue earned is given as

S(t)=\left \{ {{66000t+38000} {\ \ 0The present value is given as [tex]PV=\int\limits^a_b {S(t)e^{-rt}} \, dt

Here

  • a and b are the limits of integral which are 0 and 1 respectively
  • r is the rate of interest which is 5% or 0.05
  • S(t) is the function of value which is S(t)=\left \{ {{66000t+38000} {\ \ 0So the equation becomes[tex]PV=\int\limits^0_1 {S(t)e^{-0.05t}} \, dt\\PV=\int\limits^{0.5}_0 {(66000t+38000)e^{-0.05t}} \, dt+\int\limits^{1}_{0.5}{(71000)e^{-0.05t}} \, dt\\PV=\int\limits^{0.5}_0 {(66000t)e^{-0.05t}} \, dt+\int\limits^{0.5}_0 {(38000)e^{-0.05t}} \, dt+\int\limits^{1}_{0.5}{(71000)e^{-0.05t}} \, dt\\PV=8113.7805+18764.4669+34207.6751\\PV=61085.9225

    So the present value of revenue in the first year is $61,085.92.

    b-

    The time in which the machine pays for itself is given as

    PV=\int\limits^0_1 {S(t)e^{-0.05t}} \, dt+\int\limits^t_1 {S(t)e^{-0.05t}} \, dt\\PV=61085.9225+\int\limits^{t}_{1}{(71000)e^{-0.05t}} \, dt

    The present value is set equal to the value of machine which is given as

    $160,000 so the equation becomes:

    PV=61085.9225+\int\limits^{t}_{0}{(71000)e^{-0.05t}} \, dt\\160000=61085.9225+\int\limits^{t}_{0}{(71000)e^{-0.05t}} \, dt\\\int\limits^{t}_{0}{(71000)e^{-0.05t}} \, dt=160000-61085.9225\\\int\limits^{t}_{1}{(71000)e^{-0.05t}} \, dt=98914.07\\\\t=-\dfrac{\ln \left(0.93034\right)}{0.05}\\t=1.44496

    So the total time it would take to pay for its price is 2.44 years of 29.33 months.

6 0
3 years ago
Last year Dania Corporation's sales were $525 million. If sales grow at 10.5% per year, how large (in millions) will they be 8 y
Andru [333]

In 8 years, Dania Corporation's sales would be $936.33 million.

Solution:

Since last year sales = $525 million,

Let last year be Year 0

So, in year 0 = $525 million.

Sales grow = 7.5% per year,

Year 1,

525 x 1.075 = $564.375 million.

Year 2,

564.375 x 1.075 = $606.7 million

Year 3,

606.7 x 1.075 = $652.2 million

Year 4

652.2 x 1.075 = $701.12 million

Year 5

701.12 x 1.075 = $753.7 million

Year 6

753.7 x 1.075 = $810.23 million

Year 7

810.23 x 1.075 = $871 million

Finally in year 8

871 x 1.075 = $936.33 million

To learn more about sales visit:

brainly.com/question/14253274

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3 0
2 years ago
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