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3 years ago

Find the missing base (b1) of the trapezoid. Dimensions are in CM.

Mathematics

1 answer:

Alenkinab [10]3 years ago

5 0

Answer:

b1 = 9 cm

Step-by-step explanation:

The formula for area of a trapezoid is

A = 1/2 (b1+b2) *h

We know Area = 135 CM ^2, Height = 10 CM, b2 = 18 cm

Substituting these in

135 = 1/2 (b1+18) *10

Multiply 1/2*10

135 = 5 (b1+18)

Divide both side by 5

135/5 = 5/5 (b1+18)

27 = b1+18

Subtract 18 from each side

27-18 = b1+18-18

9 = b1

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Which table of values represents the equation Y= 2X +5?

barxatty [35]

Answer:

Step-by-step explanation:

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3 years ago

What is an angle that measures 1/2 turn

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An angle that measures 1/2 turn is 180 degree angle

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3 years ago

What is the minimum force required to prevent a ball weighing 22.6 lb from rolling down a ramp which is inclined at 39.0 degrees

Alona [7]

The correct answer is 14.2 lb which is choice D.

Let:

F = minimum force required to prevent ball from rolling down the ramp

The formula will be:

F = w * sin theta

F = w * sin (39 degrees)

F = 22.6 * sin (39)
= 14.2 lb (this is rounded to the nearest tenth)

7 0

3 years ago

A filter filled with liquid is in the shape of a vertex-down cone with a height of 9 inches and a diameter of 6 inches at its op

Alina [70]

Answer: Level of the liquid dropping at 28.28 inch/second when the liquid is 2 inches deep.

Step-by-step explanation:

Since we have given that

Height = 9 inches

Diameter = 6 inches

Radius = 3 inches

So, $\dfrac{r}{h}=\dfrac{3}{9}=\dfrac{1}{3}\\\\r=\dfrac{1}{3}h$

Volume of cone is given by

$V=\dfrac{1}{3}\pi r^2h\\\\V=\dfrac{1}{3}\pi \dfrac{1}{9}h^2\times h\\\\V=\dfrac{1}{27}\pi h^3$

By differentiating with respect to time t, we get that

$\dfrac{dv}{dt}=\dfrac{1}{27}\pi \times 3\times h^2\dfrac{dh}{dt}=\dfrac{1}{9}\pi h^2\dfrac{dh}{dt}$

Now, the liquid drips out the bottom of the filter at the constant rate of 4 cubic inches per second, ie $\dfrac{dv}{dt}=-4\ in^3$

and h = 2 inches deep.

$-4=\dfrac{1}{9}\times \pi\times (2)^2\dfrac{dh}{dt}\\\\-9\pi =\dfrac{dh}{dt}\\\\-28.28=\dfrac{dh}{dt}$

Hence, level of the liquid dropping at 28.28 inch/second when the liquid is 2 inches deep.

7 0

3 years ago

A substance has a density of 0.70 g/mL, if it has a volume of 3.0 mL, what is its mass?

Naddika [18.5K]

Answer:

Step-by-step explanation:

The mass of a substance when given the density and volume can be found by using the formula

mass = Density × volume

From the question we have

mass = 0.70 × 3

We have the final answer as

Hope this helps you

4 0

3 years ago