The answer is 3. To find the interquartile range, all you have to do is subtract your Q3-Q1. In this case, all you do is
20-17=3
X= fancy, y= plain
x+y= 7
28x+ 15y=131
solve by substitution
equation for the perpendicular Bisector of the line segment whose endpoints are (-9,-8) and (7,-4)
Perpendicular bisector lies at the midpoint of a line
Lets find mid point of (-9,-8) and (7,-4)
midpoint formula is


midpoint is (-1, -6)
Now find the slope of the given line
(-9,-8) and (7,-4)


Slope of perpendicular line is negative reciprocal of slope of given line
So slope of perpendicular line is -4
slope = -4 and midpoint is (-1,-6)
y - y1 = m(x-x1)
y - (-6) = -4(x-(-1))
y + 6 = -4(x+1)
y + 6 = -4x -4
Subtract 6 on both sides
y = -4x -4-6
y= -4x -10
equation for the perpendicular Bisector y = -4x - 10
Answer:
Vanessa is 60 and the other person is 12
Step-by-step explanation:
X + 5x = 72
6x = 72
x = 12
12 x 5 = 60
vanessa is 60
the other person is 12
60 + 12 = 72
Answer:
2 ; 10
Step-by-step explanation:
a + B = 12
a - B = 8
a = 12 - B
(12 - B) - B = 8
a = 12 - B
12 - 2B = 8
B = 2
A = 10