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Answer:
D. There is not enough information to make a conclusion about the population mean.
Step-by-step explanation:
One of the crafters Chris has a sample means of 200. This means that the average amount of yarn Chris used is 200 meters. Yet there is nothing else given about the other crafters, hence it is impossible to draw a conclusion.
Answer:
a) Because the confidence interval does not include 0 it appears that there
is a significant difference between the mean level of hemoglobin in women and the mean level of hemoglobin in men.
b)There is 95% confidence that the interval from −1.76 g/dL<μ1−μ2<−1.62 g/dL actually contains the value of the difference between the two population means μ1−μ2
c) 1.62 < μ1−μ2< 1.76
Step-by-step explanation:
a) What does the confidence interval suggest about equality of the mean hemoglobin level in women and the mean hemoglobin level in men?
Given:
95% confidence interval for the difference between the two population means:
−1.76g/dL< μ1−μ2 < −1.62g/dL
population 1 = measures from women
population 2 = measures from men
Solution:
a)
The given confidence interval has upper and lower bound of 1-62 and -1.76. This confidence interval does not contain 0. This shows that the population means difference is not likely to be 0. Thus the confidence interval implies that the mean hemoglobin level in women and the mean hemoglobin level in men is not equal and that the women are likely to have less hemoglobin than men. This depicts that there is significant difference between mean hemoglobin level in women and the mean hemoglobin level in men.
b)
There is 95% confidence that the interval −1.76 g/dL<μ1−μ2<−1.62 g/dL actually contains the value of the difference between the two population means μ1−μ2.
c)
If we interchange men and women then
- confidence interval range sign will become positive.
- μ1 becomes the population mean of the hemoglobin level in men
- μ2 becomes the population mean of the hemoglobin level in women
- So confidence interval becomes:
1.62 g/dL<μ1−μ2<1.76 g/dL.
Answer:
1. Dilate ΔABE by a factor of 2/5 to make ΔA'B'E'
2. Translate A' to Q
Step-by-step explanation:
We notice the triangles have the same orientation, so no reflection or rotation is involved. The desired mapping can be accomplished by dilation and translation:
1. Dilate ΔABE by a factor of 2/5 to make ΔA'B'E'
2. Translate A' to Q
The result will be that ΔA"B"E" will lie on top of ΔQRT, as required.
Average rate is given by,
for section A, a=1, b=3
hope this helps.
