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damaskus [11]
2 years ago
11

Ricardo borrows $1,850 for 10 months at an interest rate of 12.25%. What amount will

Mathematics
1 answer:
jonny [76]2 years ago
7 0

9514 1404 393

Answer:

  $2038.85

Step-by-step explanation:

The value of the loan at that point is given by ...

  A = P(1 +rt) . . . . . Principal P, rate r, time t (years)

  A = $1850(1 + 0.1225·(10/12)) = $2038.85

Ricardo will have paid back $2038.85 at the end of the loan period.

_____

<em>Additional comment</em>

We assume that the loan accrues simple interest and that the amount due is the sum of principal and interest at the end of the loan period.

The question is not specific as to whether interest compounds, or whether intermediate (monthly) payments are made. There are many possible ways the loan could be repaid, generally involving different amounts for the different terms.

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2x(x^4-x^2-6) what is the answer to this when foiled?
sp2606 [1]
When you foil it out you should get: 2x^5-2x^3-12x. When you factor it out completely you get: 2x(x^2-3)(x^2+2)
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3 years ago
Perform the indicated operations. Write the answer in standard form, a+bi.<br> 5-3i / -2-9i
Vsevolod [243]

\huge \boxed{\mathfrak{Answer} \downarrow}

\large \bf\frac { 5 - 3 i } { - 2 - 9 i } \\

Multiply both numerator and denominator of \sf \frac{5-3i}{-2-9i} \\ by the complex conjugate of the denominator, -2+9i.

\large \bf \: Re(\frac{\left(5-3i\right)\left(-2+9i\right)}{\left(-2-9i\right)\left(-2+9i\right)})  \\

Multiplication can be transformed into difference of squares using the rule: \sf\left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.

\large \bf \: Re(\frac{\left(5-3i\right)\left(-2+9i\right)}{\left(-2\right)^{2}-9^{2}i^{2}})  \\

By definition, i² is -1. Calculate the denominator.

\large \bf \: Re(\frac{\left(5-3i\right)\left(-2+9i\right)}{85})  \\

Multiply complex numbers 5-3i and -2+9i in the same way as you multiply binomials.

\large \bf \: Re(\frac{5\left(-2\right)+5\times \left(9i\right)-3i\left(-2\right)-3\times 9i^{2}}{85})  \\

Do the multiplications in \sf5\left(-2\right)+5\times \left(9i\right)-3i\left(-2\right)-3\times 9\left(-1\right).

\large \bf \: Re(\frac{-10+45i+6i+27}{85})  \\

Combine the real and imaginary parts in -10+45i+6i+27.

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Do the additions in \sf-10+27+\left(45+6\right)i.

\large \bf Re(\frac{17+51i}{85})  \\

Divide 17+51i by 85 to get \sf\frac{1}{5}+\frac{3}{5}i \\.

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The real part of \sf \frac{1}{5}+\frac{3}{5}i \\ is \sf \frac{1}{5} \\.

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3 0
2 years ago
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Snezhnost [94]

Answer:

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Step-by-step explanation:

Given

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  • The point (2,8)

To determine

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Using the formula

Slope = m =  [y₂ - y₁] /  [x₂ - x₁]

here:

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m =  [y₂ - y₁] /  [x₂ - x₁]

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divide  both sides by 3

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3 years ago
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romanna [79]

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6 0
3 years ago
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Answer:

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