Answer:
<u>Question 9</u>
Name the ordered pairs in the table: 3, 4, 5, 6, 7
Ordered pairs: (1,3), (2,4), (3,5), (4,6), (5,7)
Graph the equation: the attachment
Step-by-step explanation:
I don't know how to do questions 11 and 12.
Also sorry if these aren't correct.
Answer:
HEEYYYY
Step-by-step explanation:
THANK YOU SO MUCH!!! :)
Answer:0
Step-by-step explanation:
You distribute the 4 on 5&x which will then be 20. Your equation is now 20+4x=20 you then subtract the twenty so then it’s 4x=0 divide by 4 on both sides which gives you 0
// Input value is usernum.
// This code snippet sums 1 + 3 + 5 + ... + usernum
// The answer is stored in the variable summedvalue.
N = (int) (usernum+1)/2; // maximum number of integers to be summed
int *v = malloc(N*sizeof(int)); // allocate storage for array v
// Calculate the number of loop counts and assign array v..
count = 0;
k = 1;
while (1) {
if (k>usernum) { // do not extend v beyond usernum
break;
}
v(count) = k; // assign an odd integer to v, including usenum
count++;
k += 2; // k is an odd number
if k>usernum { // handle usernum as odd or even
k = usernum;
}
}
n = count; // the size of array v.
// Calculate the sum in a for loop
summedvalue = 0; // initialize summedvalue
for (i=0; i<=n; i++) {
summedvalue += v(i);
}
The median is 6. What you do is list all the numbers in order and cross one on each side out until your left with one.
