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kobusy [5.1K]
3 years ago
9

What is the inter-quartile range of the given data set? 2 3 6

Mathematics
2 answers:
Len [333]3 years ago
8 0
The answer is 3. To find the interquartile range, all you have to do is subtract your Q3-Q1. In this case, all you do is
20-17=3
myrzilka [38]3 years ago
3 0

Answer:

Option 2 is correct. The inter-quartile range of the given data set is 3.

Step-by-step explanation:

The left end of the box in a box plot represents the first quartile and right end of the box represents the third quartile.

From the given box plot is is clear that

Q_1=17

Q_3=20

Inter-quartile range of the given data set is the difference between third quartile and first quartile.

I.Q.R.=Q_3-Q_1

I.Q.R.=20-17=3

Therefore the inter-quartile range of the given data set is 3 and option 2 is correct.

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Solve the following equation​
Nata [24]

Answer:

$ \pm \frac{10}{3} $

Step-by-step explanation:

Given:

$ \frac{4}{9} - \frac{x^2}{25} $

This can be written as $ \frac{4}{9} = \frac{x^2}{25} = x^2 = 25 \times \frac{4}{9} $

$ \implies x = \pm \sqrt{25 \times \frac{4}{9} } $

$ \implies x = \pm 5 \times \frac{2}{3}  = \pm \frac{10}{3} $

6 0
3 years ago
Multiple choice question: A square mosaic is made of small glass squares. If there are 196 small squares
Anni [7]

Answer:

14 squares

Step-by-step explanation:

1. We know if the mosaic is a square shape, all sides are the same length and consist of the same amount of squares

2. Area is L×W, so in this case A×A=196

3. We can test this by replacing A with 14 and seeing if the answer is correct.

4. 14×14=196 is true

This can also be done by finding the square root of 196.

3 0
3 years ago
ASAP!!!<br><br> The distance (in units) between (−6, 2) and (8, 2).
Nesterboy [21]

Answer:

14 units

Step-by-step explanation:

6 0
4 years ago
What is the value of the expression below when y=10y=10?<br> 5y+3<br> 5y+3
Irina-Kira [14]

Answer:

53

Step-by-step explanation:

I assume the question is find the value of 5y+3 when y=10.

5y+3

5*(10)+3

= 50 + 3

=53

8 0
2 years ago
What is the amplitude and period of f(t)= -cos 3t?
Lady_Fox [76]

Answer:

option c

amplitude 1 ; period 2π/3

Step-by-step explanation:

Given in the question a function,

f(t)=-cos3t

Standard form of cosine function is

f(t)=acos(bt)

Amplitude is given by = |a|

Period of function is given by = 2π/b

So the amplitude is |-1| = 1

    the period is 2π/3 = 2π/3

3 0
3 years ago
Read 2 more answers
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