Answer:
The answer to your question is: ![\sqrt[4]{2^{3} } + 1](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B2%5E%7B3%7D%20%7D%20%2B%201)
Step-by-step explanation:
![\frac{1}{\sqrt[4]{2- 1}} x \frac{\sqrt[4]{2^{3}}+ 1 }{\sqrt[4]{2^{3}} + 1} = [tex]\frac{\sqrt[4]{2^{3}}+ 1 }{2 - 1}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B%5Csqrt%5B4%5D%7B2-%201%7D%7D%20%20x%20%5Cfrac%7B%5Csqrt%5B4%5D%7B2%5E%7B3%7D%7D%2B%201%20%7D%7B%5Csqrt%5B4%5D%7B2%5E%7B3%7D%7D%20%2B%201%7D%20%3C%2Fp%3E%3Cp%3E%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%3D%20%5Btex%5D%5Cfrac%7B%5Csqrt%5B4%5D%7B2%5E%7B3%7D%7D%2B%201%20%7D%7B2%20-%201%7D)
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Let's have the first number, the larger number, be <em>x</em>. We'll have the second, smaller number be <em>y</em>.
We know that x = y + 6, since x is 6 greater than y.
We also know that 330 = x + y.
Because x = y + 6, 330 = y + 6 + y, which simplifies to 330 = 2y + 6.
Now all we need to do is simplify the equation. First, we subtract 6 from both sides:
330 - 6 = 324
2y + 6 - 6 = 2y.
So we have 324 = 2y. Then we divide both sides by 2 to get:
162 = y
Plug in y = 162 into the equation x = y + 6 to get:
x = 162 + 6
x = 168
Let's check to make sure our answer is right. 168 is 6 more than 162. 162 + 168 equals 330. So our two numbers are 168 and 162.
The 4 in the thousands place is 10 times the 4 in the hundreds place.
Answer:
Step-by-step explanation:
The first step you want to do is get one variable by itself. We are going to start by isolating y by itself.
-3x + 9y = -27
9y = 3x - 27
y = 1/3x - 3
By isolating y by itself, you now have a function written in slope-intercept form. To graph this function, you can draw a point at (0,-3), then use rise/run to go up 1 unit and over 3 units to the next point (3,-2). You can then draw a line based on this information.
