Unsure of what you are asking!
But if the issue here is how to define a line segment, write what you do know and then reconsider "undefined terms."
A line segment is a straight line that connects a given starting point and given ending point.
If you consider a circle of radius 3 units, the radius can be thought of as the line segment connecting the center of the circle to any point on the circumference of the circle.
If the center of a given circle is at C(0,0) and a point on the circumference is given by R(3sqrt(2),3sqrt(2)), then AC is the line segment joining these two points. This line segment has length 3 and is in the first quadrant, with coordinates x=3sqrt(2) and y=3sqrt(2) describing the end point of the segment.
Answer:
y = 3/2x + 15
Step-by-step explanation:
change f(x) to 'y='
interchange 'x' and 'y' then solve for 'y':
y = 2/3x - 10
x = 2/3y - 10
x+10 = 2/3y
multiply each side by 3/2 to get:
y = 3/2x + 15
We need Probability of drawing a heart Or drawing a face card other than a heart.
This is 1/4 + 9/52 = 11/26
C is the correct choice.
<span>The vertex of the parabola is the highest or lowest point of the graph.
</span><span>y=-4x^2+8x-12 = -4 (x^2 -2x +3)
Lets work with this now: </span>x^2 -2x +3
x^2 -2x +3 -> what is the closeset perfect square?
x^2 -2x +1 = (x-1)^2
So
x^2 -2x +3 = (x-1)^2 +2
Replacing to original
y=-4x^2+8x-12 = -4 (x^2 -2x +3) = -4 ((x-1)^2 +2) = -4 (x-1)^2 - 8
The min or max point is where the squared part = 0
So when x=1 , y= -4*0-8=-8
This will be the max of the parabola as there is - for the highest factor (-4x^2)
The max: x=1, y= -8
Answer:
y=(x+5)²/6 + 1/3
Step-by-step explanation:
Use the distance formula to plug in the values you know:
√(y+1)² =√(x+5)² +( y-2)²
the square roots cancel out
(y+1) ²= (x+5)² +(y-2)²
(y+1) (y-1)= (x+5)² + (y-2) (y-2)
y²+2y+1= (x+5)² + y² -4y+4
the y² cancel out
2y+ 4y = (x+5)² + 4-1
6y= (x+5)² +3
y= (x+5)² /6+ 1/3
