All categories

3 years ago

Alexis spends 4 hours a day watching tv. how many seconds does she watch tv in a week

Mathematics

1 answer:

olga_2 [115]3 years ago

8 0

Answer:

100,800 seconds a week

Step-by-step explanation:

So first you would figure out how many minutes she spends each day watching so, 60 x 4 = 240

then how many seconds a day so 240 x 60 = 14,400 a day

now how many seconds a week 14,400 x 7 = 100,800

You might be interested in

in the set of first ten natural numbers 1 1 1 2 3 4 5 6 7 8 9 10. a what is percent of numbers are odd? b what percent of number

Fittoniya [83]

Answer:

a)50%,b)70%

Step-by-step explanation:

odd=5

10=100%

5×100=500/10

=50%

10=100%

(7×100)/10=70

4 0

3 years ago

chose the answer that best completes the sentence. If you know a root of a function is -2+square root of 3t, then ___? A.) 2+squ

Temka [501]

Answer:

D. -2 - (square root of 3) is a known root

Step-by-step explanation:

It’s D on edge

7 0

4 years ago

I need help I been hitting a roadblock for the past hour. Can anyone help me?

snow_lady [41]

Answer:

hhuh

Step-by-step explanation:

7 0

3 years ago

Five standard six-sided dice are rolled. We are told there is no three-of-a-kind, but there is a pair of dice that show the same

Neko [114]

The probability that after re-rolling these three dice, at least three of the five dice show the same value is $\frac{4}{9}$

Of the three dice rolled, one may match the original pair and two are different, and this can occur three ways:

$(\frac16 \times \frac56 \times \frac56 ) + ( \frac56 \times \frac16 \times \frac56 ) + ( \frac56 \times \frac 56 \times \frac 16 ) = \frac {75}{216}$

[ where $\frac{1}{6}$ is the probability of matching the first two and $\frac{5}{6}$ is the probability of not matching the first two ]

Or, two may match the original pair and one is different

$( \frac16 \times \frac16 \times \frac 56 ) + ( \frac16 \times \frac56 \times \frac 16 ) + ( \frac56 \times \frac16 \times \frac16 ) = \frac {15}{216}$

Or, all three may match the original pair

$( \frac 16 \times \frac 16 \times \frac 16 ) = \frac {1}{216}$

Or, all three may be the same, but not match the original pair:

$( \frac 56 \times \frac 16 \times\frac 16 ) = \frac {5}{216}$

[ where $\frac{5}{6}$ is the probability of getting a new number and $\frac{1}{6}$ is the probability of matching that new number ]

Adding these together: $\frac {75}{216} + \frac {15}{216} + \frac 1{216} + \frac 5{216} = \frac {96}{216} = \frac 49$

To learn more about probability with the given link

brainly.com/question/11234923

#SPJ4

3 0

2 years ago

A new car battery is sold with a two-year warranty whereby the owner gets the battery replaced free of cost if it breaks down du

lara [203]

Answer:

a) 0.1587 = 15.87% probability that a battery will break down during the warranty period.

b) The expected profit of the auto store on a battery is of $15.239.

c) The expected monthly profit on batteries if the auto store sells an average of 500 batteries a month is of $7,619.50.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

The life of batteries is known to be normally distributed with a mean and a standard deviation of 40 and 16 months, respectively.

This means that $\mu = 40, \sigma = 16$

a. What is the probability that a battery will break down during the warranty period?

Two year warranty, that is, 24 months. This probability is the pvalue of Z when X = 24. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{24 - 40}{16}$

$Z = -1$

$Z = -1$ has a pvalue of 0.1587.

0.1587 = 15.87% probability that a battery will break down during the warranty period.

b. What is the expected profit of the auto store on a battery?

1 - 0.1587 = 0.8413 probability of a profit of $20.

0.1587 probability of a loss of $10. So

$E = 0.8413*20 - 0.1587*10 = 15.239$

The expected profit of the auto store on a battery is of $15.239.

c. What is the expected monthly profit on batteries if the auto store sells an average of 500 batteries a month?

Multiplying the average for a battery by 500. So

15.239*500 = $7,619.50

The expected monthly profit on batteries if the auto store sells an average of 500 batteries a month is of $7,619.50.

5 0

3 years ago