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Irina-Kira [14]
3 years ago
5

Expand and simplify (x-3)(2x+1)(3x_2)​

Mathematics
1 answer:
castortr0y [4]3 years ago
5 0

Step-by-step explanation:

Did you mean

= (x - 3)(2x + 1)(3x - 2)

= (2x² + x - 6x - 3)(3x - 2)

= (2x² - 5x - 3)(3x - 2)

= 6x³ - 4x² - 15x² + 10x - 9x + 6

= 6x³ - 19x² + x + 6

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Answer:

24

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8 0
3 years ago
Aaron used the Pythagorean theorem to find the height of a tree. He calculated that the tree was √625 feet tall. Which of the fo
frutty [35]

Answer:

25 feet

Step-by-step explanation:

8⅓ yards

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3 0
3 years ago
Yeah I don’t get this
umka2103 [35]

using pythagorean theorem

a^2 + b^2 = c^2

(12x)^2 + (16x)^2 = 10^2

square each term

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divide by 400 on each side

x^2 = 1/4

take the square root on each side

x = 1/2


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8 0
3 years ago
Find the area lying outside r=6cos(theta) and inside r=3+3cos(theta)
Sloan [31]
The area bounded by the 2 parabolas is A(θ) = 1/2∫(r₂²- r₁²).dθ between limits θ = a,b... 

<span>the limits are solution to 3cosθ = 1+cosθ the points of intersection of curves. </span>
<span>2cosθ = 1 => θ = ±π/3 </span>

<span>A(θ) = 1/2∫(r₂²- r₁²).dθ = 1/2∫(3cosθ)² - (1+cosθ)².dθ </span>
<span>= 1/2∫(3cosθ)².dθ - 1/2∫(1+cosθ)².dθ </span>
<span>= 9/8[2θ + sin(2θ)] - 1/8[6θ + 8sinθ +sin(2θ)] .. </span>
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<span>= 3θ/2 +sin(2θ) - sin(θ) </span>

<span>Area = A(π/3) - A(-π/3) </span>
<span>= 3π/6 + sin(2π/3) -sin(π/3) - (-3π/6) - sin(-2π/3) + sin(-π/3) </span>
<span>= π.</span>
7 0
4 years ago
100 points, put nonsense, get reported. Susan wants to build a floor to put at the bottom of her tree house. She made the scale
Elanso [62]

Divide the length of the scale drawing by the scale (2.5) then multiply that by the scale feet (3)


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3 0
3 years ago
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