3 years ago

Expand and simplify (x-3)(2x+1)(3x_2)

Mathematics

1 answer:

castortr0y [4]3 years ago

5 0

Step-by-step explanation:

Did you mean

= (x - 3)(2x + 1)(3x - 2)

= (2x² + x - 6x - 3)(3x - 2)

= (2x² - 5x - 3)(3x - 2)

= 6x³ - 4x² - 15x² + 10x - 9x + 6

= 6x³ - 19x² + x + 6

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If f(x)f(x) is an exponential function where f(1.5)=5f(1.5)=5 and f(7.5)=79f(7.5)=79, then find the value of f(3)f(3), to the ne

stiv31 [10]

Answer: $7.93$

Step-by-step explanation:

Given

$f(x)$ is an exponential function. Suppose $f(x)$ is $ae^{bx}$

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$\Rightarrow 5=ae^{1.5b}\\\Rightarrow \ln 5=\ln a-1.5b\quad \ldots(i)$

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$\Rightarrow 79=ae^{7.5b}\\\Rightarrow \ln(79)=\ln a+7.5b\quad \ldots(ii)$

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Expand and simplify (x-3)(2x+1)(3x_2)​

Expand and simplify (x-3)(2x+1)(3x_2)