There were a total of eight teams in the tournament.
Answer:
The weight of the enlarged paperweight is
Step-by-step explanation:
we know that
If two figures are similar, then the ratio of its volumes (or its weights) is equal to the scale factor elevated to the cube
Let
z-----> the scale factor
x ----> the enlarged paperweight weight
y ----> the original paperweight weight
we have
substitute and solve for x
Lets check all the choices:
A. subtraction:
(3x+2)-(4y-11)=3x+2-4y+11=3x-4y+13
similarly, (4y-11)-(3x+2)=-3x+4y-13
both are polynomials (of 2 variables)
B. (3x+2)(4y-11)=12xy-33x+8y-22, which is a polynomial
C. (3x+2)+(4y-11)=3x+2+4y-11=3x+4y-9, which is a polynomial
D.
both
and
are rational expressions in 2 variables, not polynomials
Answer: D
Answer:
it d j=6
Step-by-step explanation:
5+3=8
48/8
6