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wel
3 years ago
10

Point C is located at (1, 2) and point D is located at (-4, -2). Find the X value for the point that is 1/4 the distance from po

int C to point D
Mathematics
1 answer:
kolbaska11 [484]3 years ago
8 0
D (-4; -2)
C (1; 2)
M (x; y)
DM+MC=CD
CM:MD=1:3
M: x= x(C)-(x(C) - x(D))/4=1-(1-(-4))/4=1 - (6/4)=1 - 1,5= - 0,5
M: y=y(C)-(y(C) - y(D))/4=2-(2-(-2))/4=2 - (4/4)=2 - 1=1
M(x; y)=M( -0,5; 1)
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The expression can be simplified as:

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2 years ago
The results of joes survey show that baseball is the favorite sport for 18 out of 25 people. What percent do not like sports?
charle [14.2K]

well if 18 out of 25 like it, then the remaining 7 doesn't like it, namely 7 out of 25.

if we take 25 to be the 100%, what is 7 off of if in percentage?

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3 years ago
8.7/2=q/4 what is Q and give me work plez
ZanzabumX [31]
8.7/2=q/4
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refine the equation: 2q=34.8
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8 0
2 years ago
HELPPP
GalinKa [24]

Answer:

HL (Hypotenuse Leg)

Step-by-step explanation:

You have BC=CD (Because of reflexive property), AC=DC, and measure of BAC is equal to the measure of BDC, which is 90 degrees. Since these triangles are right and they have a hypotenuse and a leg congruent, you can say that they are congruent because of HL.

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2 years ago
Suppose that the hourly wages of fast food workers are normally distributed with an unknown mean and standard deviation. The wag
Nutka1998 [239]

Answer: 1.303639

Step-by-step explanation:

The t-score for a level of confidence (1-\alpha) is given by :_

t_{(df,\alpha/2)}, where df is the degree of freedom and \alpha is the significance level.

Given : Level of significance : 1-\alpha:0.80

Then , significance level : \alpha: 1-0.80=0.20

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Then , the degree of freedom for t-distribution: df=n-1=40-1=39

Using the normal t-distribution table, we have

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Thus, the t-score should be used to find the 80% confidence interval for the population mean =1.303639

8 0
3 years ago
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