Point C is located at (1, 2) and point D is located at (-4, -2). Find the X value for the point that is 1/4 the distance from po
int C to point D
1 answer:
D (-4; -2)
C (1; 2)
M (x; y)
DM+MC=CD
CM:MD=1:3
M: x= x(C)-(x(C) - x(D))/4=1-(1-(-4))/4=1 - (6/4)=1 - 1,5= - 0,5
M: y=y(C)-(y(C) - y(D))/4=2-(2-(-2))/4=2 - (4/4)=2 - 1=1
M(x; y)=M( -0,5; 1)
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the bottom one is (3x−2)(3x+2)
Step-by-step explanation: