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trapecia [35]
2 years ago
8

Clayton Burrington purchased the following school supplies on s

Mathematics
1 answer:
vladimir1956 [14]2 years ago
4 0

Answer:

The answer is not reasonable.

The error that Clayton made was that he accidentally added all of the products that had a saved price tag on it, he did not find the difference between the old price and the new, sales price.

Step-by-step explanation:

Hope this helps :) Mark me brainliest if anyone else answers this question.

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Abcd is a rectangle. Find the length of each diagonal. .AC= 3y/5 BD=3y-4
-Dominant- [34]
I hope this helps you

3 0
3 years ago
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Vsevolod [243]
The unknown is 2% and sorry
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3 years ago
Al factorizar el trinomio cuadrado perfecto, obtenemos el siguiente resultado: (que no se como resolver) xd algun pro que sepa r
PolarNik [594]

Answer:

\displaystyle \frac{100}{81}m^8p^{12}q^{16}z^2-\frac{20}{63}m^5p^7q^8z^5+ \frac{1}{49}m^2p^2z^8=\left(\frac{10}{9}m^4p^{6}q^{8}z-\frac{1}{7}mpz^4\right)^2

Step-by-step explanation:

<u>Trinomio Cuadrado Perfecto</u>

El producto notable llamado cuadrado de un binomio se expresa como:

(a-b)^2=a^2-2ab+b^2

Si se tiene un trinomio, es posible convertirlo en un cuadrado perfecto si cumple con las condiciones impuestas en la fórmula:

* El primer término es un cuadrado perfecto

* El último término es un cuadrado perfecto

* El segundo término es el doble del proudcto de los dos términos del binomio.

Tenemos la expresión:

\displaystyle \frac{100}{81}m^8p^{12}q^{16}z^2-\frac{20}{63}m^5p^7q^8z^5+ \frac{1}{49}m^2p^2z^8

Calculamos el valor de a como la raiz cuadrada del primer término del trinomio:

\displaystyle a=\sqrt{\frac{100}{81}m^8p^{12}q^{16}z^2}

\displaystyle a=\frac{10}{9}m^4p^{6}q^{8}z

Calculamos el valor de a como la raiz cuadrada del primer término del trinomio:

\displaystyle b=\sqrt{\frac{1}{49}m^2p^2z^8

\displaystyle b=\frac{1}{7}mpz^4

Nos cercioramos de que el término central es 2ab:

\displaystyle 2ab=2\frac{10}{9}m^4p^{6}q^{8}z\frac{1}{7}mpz^4

Operando:

\displaystyle 2ab=\frac{20}{63}m^5p^7q^8z^5

Una vez verificado, ahora podemos decir que:

\displaystyle \frac{100}{81}m^8p^{12}q^{16}z^2-\frac{20}{63}m^5p^7q^8z^5+ \frac{1}{49}m^2p^2z^8=\left(\frac{10}{9}m^4p^{6}q^{8}z-\frac{1}{7}mpz^4\right)^2

5 0
2 years ago
Which value of y below is the solution to the system shown below. A) y=6 B) y=-1 C) y=-4 D) y=8
Grace [21]

Answer:

D

Step-by-step explanation:

given the 2 equations

x + 2y = 27 → (1)

2x + 3y = 46 → (2)

Rearrange (1) expressing x in terms of y by subtracting 2y from both sides

x = 27 - 2y ← substitute into (2)

2(27 - 2y) + 3y = 46

54 - 4y + 3y = 46

54 - y = 46 ( subtract 54 from both sides )

- y = - 8 ( multiply both sides by - 1 )

y = 8 → D

4 0
3 years ago
What is the recursive formula of the arithmetic sequence 0,11,22,33,
ArbitrLikvidat [17]

Answer:

f(1)=0

f(x+1)=f(x)+11

7 0
3 years ago
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