All categories

3 years ago

Write the numbers 1/16, -5/2, -2 1/3, and 16 least to greastest

Mathematics

2 answers:

tiny-mole [99]3 years ago

6 0

Answer:

-2 1/3, -5/2, 1/16, 16

The more negative the number gets, the lesser it would be.

morpeh [17]3 years ago

6 0

Answer:

-5/2, -2 1/3, 1/16, 16

Step-by-step explanation:

the first 2 # are negative so the largest negative goes first -5/2=-2 1/2 then -2 1/3 then 1/16 then 16

You might be interested in

Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the corre

Alex_Xolod [135]

Answer:

what are the choices

Step-by-step explanation:

8 0

3 years ago

3.5 multiplied by 2y

Rama09 [41]

Answer:

Step-by-step explanation:

3 0

3 years ago

What are the parallel sides of a trapezoid

saul85 [17]

Answer:

Parallel means that the lines will never cross. If we look at a traditional trapezoid, the top side and the bottom side are straight lines that will never cross one another. The left and right sides are slanted towards one another, to they are not parallel.

Hope this helped. : )

3 0

3 years ago

Frank invested $30,000 at 4% simple interest. How much interest will he earn each year?

Oduvanchick [21]

Answer:

$1200 interest

Step-by-step explanation:

$30,000 divided by 100 = 300 , 300 multipled by 4 = 1200 , thats how to find what 4% would be

3 0

2 years ago

A = 1011 + 337 + 337/2 +1011/10 + 337/5 + ... + 1/2021

egoroff_w [7]

The sum of the given series can be found by simplification of the number

of terms in the series.

A is approximately <u>2020.022</u>

Reasons:

The given sequence is presented as follows;

A = 1011 + 337 + 337/2 + 1011/10 + 337/5 + ... + 1/2021

Therefore;

$\displaystyle A = \mathbf{1011 + \frac{1011}{3} + \frac{1011}{6} + \frac{1011}{10} + \frac{1011}{15} + ...+\frac{1}{2021}}$

The n + 1 th term of the sequence, 1, 3, 6, 10, 15, ..., 2021 is given as follows;

$\displaystyle a_{n+1} = \mathbf{\frac{n^2 + 3 \cdot n + 2}{2}}$

Therefore, for the last term we have;

$\displaystyle 2043231= \frac{n^2 + 3 \cdot n + 2}{2}$

2 × 2043231 = n² + 3·n + 2

Which gives;

n² + 3·n + 2 - 2 × 2043231 = n² + 3·n - 4086460 = 0

Which gives, the number of terms, n = 2020

$\displaystyle \frac{A}{2} = \mathbf{ 1011 \cdot \left(\frac{1}{2} +\frac{1}{6} + \frac{1}{12}+...+\frac{1}{4086460} \right)}$

$\displaystyle \frac{A}{2} = 1011 \cdot \left(1 - \frac{1}{2} +\frac{1}{2} - \frac{1}{3} + \frac{1}{3}- \frac{1}{4} +...+\frac{1}{2021}-\frac{1}{2022} \right)$

Which gives;

$\displaystyle \frac{A}{2} = 1011 \cdot \left(1 - \frac{1}{2022} \right)$

$\displaystyle A = 2 \times 1011 \cdot \left(1 - \frac{1}{2022} \right) = \frac{1032231}{511} \approx \mathbf{2020.022}$

A ≈ <u>2020.022</u>

Learn more about the sum of a series here:

brainly.com/question/190295

8 0

2 years ago

Read 2 more answers