Write the numbers 1/16, -5/2, -2 1/3, and 16 least to greastest

Mathematics

2 answers:

tiny-mole [99]3 years ago

6 0

Answer:

-2 1/3, -5/2, 1/16, 16

The more negative the number gets, the lesser it would be.

morpeh [17]3 years ago

6 0

Answer:

-5/2, -2 1/3, 1/16, 16

Step-by-step explanation:

the first 2 # are negative so the largest negative goes first -5/2=-2 1/2 then -2 1/3 then 1/16 then 16

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13. Diberi v = u + at, cari nilai t apabila v = v = 42 u=-8 dana - 5. A.10 B.8 C.6 D.4

LiRa [457]

Answer:

Lol mcm soalan kamu salah. Pilih A je

Step-by-step explanation:

v = 42
u = -8
a = -5

Masukkan nilai tersebut dalam persamaan v = u + at,

42 = -8 + (-5)t

50 = -5t

t = -10

3 0

3 years ago

Find the distance of the line segment joining the two points (-4 /2 - /12) and (/32, 2/3)

astraxan [27]

Answer: $4\sqrt{3}$ .

Step-by-step explanation:

Distance formula : Distance between points (a,b) and (c,d) is given by :-

$D=\sqrt{(d-b)^2+(b-a)^2}$

Distance between points $(-4\sqrt{2},\sqrt{12}) \text{ and }(-\sqrt{32}, 2\sqrt{3})$ .

$D=\sqrt{(2\sqrt{3}-(-\sqrt{12}))^2+(-\sqrt{32}-(-4\sqrt{2}))}\\\\=\sqrt{(2\sqrt{3}+\sqrt{2\times2\times3})^2+(-\sqrt{4\times4\times2}+4\sqrt{2})^2}\\\\=\sqrt{(2\sqrt{3}-\sqrt{2^2\times3})^2+(-\sqrt{4^2\times2}+4\sqrt{2})^2}\\\\=\sqrt{(2\sqrt{3}+2\sqrt{3})^2+(-4\sqrt{2}+4\sqrt{2})^2}\\\\=\sqrt{(4\sqrt{3})^2+0}\\\\=4\sqrt{3}\text{ units}$