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pochemuha
3 years ago
11

What is ten times as much as 0.09

Mathematics
1 answer:
klemol [59]3 years ago
5 0
10x0.09=0.9
..................
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Express 321,000,000,000 in scientific notation
stiks02 [169]
3.21 + 10 × 11

3.21 + {10}^{11}
6 0
4 years ago
Find three consecutive odd integers such that the sum of those numbers is 135​
snow_lady [41]

Answer: 43,45,47.

Step-by-step explanation:

6 0
3 years ago
7,
Anna007 [38]

Answer:

1/12

Step-by-step explanation:

the chances of rolling a 3 is 1/6

there are 3 numbers more than 3 on a number die, 4,5, and 6

which is 3/6 or 1/2 if you decide to simplify

to find the probability you want you have to multiply the fractions by each other

1/6x1/2=1/12

5 0
2 years ago
A store is having a 10% off sale. It gives an additional 20% off for an item that is above $100 after the first 10% discount.A j
Law Incorporation [45]
There are several information's already given in the question. Based on those information's, the answer can be easily deduced.

Cost of the jacket = $124.99
Percentage of discount given at the beginning = 10%
Amount of initial discount given = (10/100) * 124.99
                                                   = 12.499 dollars
                                                   = 12.50 dollars
Then
Price of the jacket after the initial discount = 124.99 - 12.50
                                                                   = 112.49 dollars
Percentage of additional discount = 20%
Amount of additional discount = (20/100) * 112.49
                                                = 22.50 dollars
Total amount saved on buying the jacket = 12.50 + 22.50
                                                                  = 35 dollars
I hope that this is the answer that you were looking for and the answer has actually come to your desired help.
8 0
3 years ago
Which expression is equivalent to 7x - 5 - 9x + 2? -2x - 7 2x - 7 -2x - 3 -2x + 3
gulaghasi [49]
<span>7x - 5 - 9x + 2 = -2x - 3 ..............combine like terms

answer
</span><span>-2x - 3</span>
8 0
3 years ago
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