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ki77a [65]
3 years ago
12

Please help asap!:)) and show work!

Mathematics
1 answer:
Vikki [24]3 years ago
8 0

Answer:

The other acute angle = 33 1/3°

Step-by-step explanation:

Hard to read the angle measure.  

one acute angle = 56 2/3°      x =  the second acute angle

Find the other acute angles.

The two acute angles sum in a right triangle = 90°  

56 2/3° + x° = 90°

x =  90 - 56 2/3

x = 89 3/3° - 56 2/3°

x = 33 1/3°

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quester [9]

Answer:

C

Step-by-step explanation:

7*7=49

6 0
3 years ago
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Points (-1,2), (-4,7), (-3,1), (-2,4) lie in ______ quadrant
dalvyx [7]

Answer:

they lie in 2nd quadrant

hope it helps

5 0
3 years ago
For a moving object,When. The force acting on the object varies directly with the object's acceleration. When a force of 64 N ac
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Answer:

72 N

Step-by-step explanation:

From the question.

Force is directly proportional to acceleration, with the mass of the object constant.

F α a

F = ka

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Where F₁ = Initial force, a₁ = initial acceleration. F₂ = final force, a₂ = Final acceleration.

make F₂ the subject of the equation

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Given; F₁ = 64 N, a₁ = 8 m/s², a₂ = 9 m/s²

Substitute these values into equation 2

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5 0
3 years ago
What is the value of x? <br> 20 <br> 35<br> 60<br> 70
Brilliant_brown [7]

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Step-by-step explanation:

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5 0
3 years ago
Y=x+1 and y=-x-3 in graphing,Substitution,and elemination
marysya [2.9K]

\left\{\begin{array}{ccc}y=x+1\\y=-x-3\end{array}\right\\\\GRAPHING\ \text{(look at the picture)}\\\\y=x+1\\for\ x=0\to y=0+1=0\to(0,\ 1)\\for\ x=-1\to y=-1+1=0\to(-1,\ 0)\\\\y=-x-3\\for\ x=0\to y=-0-3=-3\to(0,\ -3)\\for\ x=-3\to y=-(-3)-3=0\to(-3,\ 0)\\\\Solution:\ (-2,\ -1)


SUBSTITUTION\\\\\left\{\begin{array}{ccc}y=x+1\\y=-x-3\end{array}\right\\\\\text{substitute}\ y=-x-3\ \text{to the first equation}\\\\-x-3=x+1\ \ \ \ |+3\\-x=x+4\ \ \ \ |-x\\-2x=4\ \ \ \ |:(-2)\\x=-2\\\\\text{substitute the value of x to the second equation}\\\\y=-(-2)-3=2-3=-1\\\\Solution:\ (-2,\ -1)


ELIMINATION\\\\\underline{+\left\{\begin{array}{ccc}y=x+1\\y=-x-3\end{array}\right}\ \ \ |\text{add both sides of the equations}\\.\ \ \ \ 2y=-2\ \ \ \ |:2\\.\ \ \ \ \ \ y=-1\\\\\text{put the value of y to the first equation}\\\\-1=x+1\ \ \ \ |-1\\x=-2\\\\Solution:\ (-2,\ -1)

5 0
3 years ago
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