Ok, 1 bionimial theorem coming right up
for a binomial expansion of (a+b)^n
the kth term is


means

n is 5
4th term
4-1=3
and a=2x
b=5
so



(10)(4x^2)(125)
5000x^2 is the 4th term
Answer:
Step-by-step explanation:
7/4 ÷ 8/7
To divide fraction multiply the first fraction by the reciprocal of the second fraction:
7/4 x 7/8 = (7x7) / (4x8) = 49/32
In this relation we have two ordered pairs:
( 5, 7 ) and ( 5, 8 )
For x = 5 : f ( x ) = 7 and also for x = 5, f ( x ) = 8. This is not possible for a function.
Answer:
b ) No. The relation is not a function.