They will be 15 miles apart after one hour if they left the same point at the same time.
<h3>How do we measure and calculate the distance in Geometry?</h3>
The distance between two points in geometry can be calculated by using the Pythagoras theorem.
Mathematically, the Pythagoras theorem can be expressed as:
where;
- x and y are opposite and adjacent sides respectively.
d = 15 miles
Therefore, we can conclude that they will be 15 miles apart after one hour if they left the same point at the same time.
Learn more about calculating the distance between two points here:
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Answer: Hello!
In a normal distribution, between the mean and the mean plus the standar deviation, there is a 34.1% of the data set, between the mean plus the standar deviation, and the mean between two times the standard deviation, there is a 16.2% of the data set, and so on.
If our mean is 16 inches, and the measure is 26 inches, then the difference is 10 inches between them.
a) if the standar deviation is 2 inches, then you are 10/2 = 5 standar deviations from the mean.
b) yes, is really far away from the mean, in a normal distribution a displacement of 5 standar deviations has a very small probability.
c) Now the standar deviation is 7, so now 26 is in the range between 1 standar deviation and 2 standar deviations away from the mean.
Then this you have a 16% of the data, then in this case, 26 inches is not far away from the mean.
46/287.5 = .16
.16x287.5 = 46
The answer is 16%
Answer:
ΔT = ΔT0 e^-K T
As I understand Newton's Law of Cooling
ΔT at any time is the difference between the temperature and the surroundings
Originally ΔT0 = 95 - 22 difference between 95 and room temperature
65 - 22 = 33 = 73 e^-KT where t is time to cool to 65 deg
ln (33/73) = -KT K = .794 / 5 = .159 where 5 is time to cool to 65 deg
40 - 22 = 73 e^-.159 T where t is time to cool to 40 deg
18 = 73 e^-.159 T
ln (18 / 73) = -.159 T
T = 8.8 min
It would take 8.8 min for the object to cool to 40 deg C
Suppose the object cooled from 95 to 90 deg, then
ln 68 / 73 = -.159 T and T = .45 min
Answer:
42
Step-by-step explanation:
The height of the pole is 4 times shorter than the length of the shadow 20÷5=4
The height of the building must be 4 times shorter than its shadow length 168÷4=42
