A rectangle has a length of 1.5abc and a width of 10abc find the area of the rectangle
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On solving the equations y = (-1/2)x + and 3x - 4y = 12 graphically , the solution is (6 , 3/2) .
In the question ,
it is given that
the equations are y = (-1/2)x + and 3x - 4y = 12
which can be written as y = (-1/2)x + 9/2 and 3x - 4y = 12
to plot the graph of the given equations , we need intercept .
For the equation y = (-1/2)x + 9/2
when x= 0 , y = (-1/2)(0) + 9/2 = 9/2
when y = 0 ,
0 = (-1/2)x + 9/2
(1/2)x = 9/2
x = 9
the points are (0 , 9/2) and (9 , 0)
For the equation 3x - 4y = 12
when x = 0 , 3(0) - 4y = 12
-4y = 12
y = -3
when y = 0 , 3x -4(0) = 12
3x = 12
x = 4
the points are (0,-3) and (4,0) .
after plotting the lines on the graph , we can see that the both the lines intersect at the point (6 , 3/2) ,
Therefore , On solving the equations y = (-1/2)x + and 3x - 4y = 12 graphically , the solution is (6 , 3/2) .
The given question is incomplete , the complete question is
Consider this equation y = (-1/2)x + and 3x - 4y = 12 .
Solve the system by graphing. label each graph.
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