__________ is not considered a driving distraction.
2 answers:
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Answer:
Materials -> R1 = 100 Ω, NPN BJT 2N2222, R3 = light-sensitive resistor, R4 = 120 KΩ, 5 V battery, red led
Design -> please see the image attached
Explanation:
We use LTspice to simulate the circuit that consists of a voltage divider in the gate of the transistor to change the operation region of the BJT accordingly to the resistance of the light-sensitive resistor; when R3 (light-sensitive resistor) has low resistance the voltage of the gate and emitter is approximately the same and the transistor is in a Cut-off state, when R3 increases its resistance the voltage of the gate start to rise and as a result, there is in a Forward-active state; a diode is placed on the collector with a small resistance R1 and whenever the transistor is active the led is going to turn on.
Note: If you need more current for the led you could reduce the value of R4, this will produce that lower values of R3 activate the transistor, you can adjust the circuit just by changing the value of R4, therefore, I highly recommend to use a potentiometer for R4 in the range of 10-300 K.
Explanation:
The given data is as follows.
Length (l) = 37.5 mm, Journal diameter (d) = 75 mm
Diameter of bushing (D) = 75.1 mm, Speed (N) = 720 rpm,
Load (F) = 2 kN
Dynamic viscosity of SAE 20 at is 12.2 cp
Clearance =
c =
= 0.05 mm
Bearing pressure will be calculated as follows.
Bearing pressure (p) =
=
=
Now, sommerfield number (S) will be calculated as follows.
S =
=
= 0.006
As,
Now, using Raimondi and John Boyd data the values for other variables will be obtained.
Minimum film thickness variable = = 0.03
Therefore, minimum film thickness
= 0.0015 mm
As, = 0.126
Hence, maximum lubricant pressure will be calculated as follows.
=
Due to friction, the heat loss rate will be as follows.
kW
According to coefficient of friction variable =
f =
=
= 0.000813
Therefore, heat loss will be calculated as follows.
Heat loss =
= 4.6 Watt