1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Blababa [14]
3 years ago
15

Under the right conditions, it is possible, due to surface tension, to have metal objects float on water. Consider placing a sho

rt length of a small diameter steel (sp. wt.=500 lb/ft3) rod on a surface of water. What is the maximum diameter, Dmax⁡, that the rod can have before it will sink? Assume that the surface tension forces act vertically upward. Note: A standard paper clip has a diameter of 0.036 in. Partially unfold a paper clip and see if you can get it to float on water. Do the results of this experiment support your analysis?
Engineering
1 answer:
stiv31 [10]3 years ago
4 0

Answer:

D = 0.060732 in

Explanation:

given data

sp. wt. = 500 lb/ft³

diameter = 0.036 in

solution

we get here maximum diameter of rod that is express as

D = \sqrt{\frac{8 \sigma }{\pi y}}   ......................1

here \sigma surface tension of water at 60⁰f  = 5.03 × 10^{-3}  lb/ft and y = 500 lb/ft³

so put here value and we will get

D = \sqrt{\frac{8 \times 5.03 \times 10^{-3} }{\pi \times 500}}

D = 0.005061 ft

D = 0.060732 in

You might be interested in
Entor" by
IrinaVladis [17]

Answer:

To generalize your thought about answer. in technology

Explanation:

4 0
3 years ago
The disk of radius 0.4 m is originally rotating at ωo=4 rad/sec. If it is subjected to a constant angular acceleration of α=5 ra
Lina20 [59]

Answer:32.4m/s^2

Explanation:

Given data

radius\left ( r\right )=0.4m

Intial angular velocity\left ( \omega_0\right )=4rad/s

angular acceleration\left ( \alpha\right )=5rad/s^2

angular velocity after 1 sec

\omega=\omega_0+\alpha\times\t

\omega=4+5\left ( 1\right )

\omega=9rad/s

Velocity of point on the outer surface of disc\left ( v\right )=\omega_0\timesr

v=9\times0.4 m/s=3.6m/s

Normal component of acceleration\left ( a_c\right )=\frac{v^2}{r}

a_c=\frac{3.6\times3.6}{0.4}=32.4m/s^2

3 0
4 years ago
Suppose we are managing a consulting team of expert computer hackers, and each week we have to choose a job for them to undertak
lina2011 [118]

Answer:

if number == 1

  then

  tempSolution= max(l[number],h[number])

else if number == 2 then

  tempSolution= max(optimalPlan(1, l, h)+ l[2], h[2])

else

  tempSolution= max(optimalPlan(number − 1, l, h) + l[number], optimalPlan(number − 2, l, h) + h[number])

end if

return Value

FindOptimalValue(number, l, h)

for itterator = 1 ! number do

  tempSolution[itterator] = 0

end for

for itterator = 1 ! number do

  if itterator == 1 then

      tempSolution[itterator] max(l[itterator], h[itterator])

  else if itterator == 2 then

      tempSolution[itterator] max(tempSolution[1] + l[2], h[2])

  else

      tempSolution[itterator] max(tempSolution[itterator − 1] + l[itterator], tempSolution[itterator − 2] + h[itterator])

  end if

end for

return Value[number]

OPtimalPlan(number, l, h, Value)

for itterator = 1 ! number do

  WeekVal[itterator]

end for

if tempSolution[number] − l[number] = tempSolution[number − 1] then

  WeekVal[number] ”Low stress”

  OPtimalPlan(number-1, l, h, Value)

else

  WeekVal[number] ”High stress”

  OPtimalPlan(number-2, l, h, Value)

end if

return WeekVal

7 0
3 years ago
Answer: D because you need an explanation <br> Explanation: Please I'll mark Brainliest
mylen [45]

Answer:Could you give a picture or something so I could answer.

Explanation:

6 0
3 years ago
(Laminar flow) A fluid flows through two horizontal pipes of equal length which are connected together to form a pipe of length
EastWind [94]

This question is incomplete, the complete question is;

(Laminar flow) A fluid flows through two horizontal pipes of equal length which are connected together to form a pipe of length 2l. The flow is laminar and fully developed. The pressure drop for the first pipe is 1.657 times greater than it is for the second pipe. If the diameter of the first pipe is D, determine the diameter of the second pipe.

D₃ = _____D.

{ the tolerance is +/-3% }

Answer:

the diameter of the second pipe D₃ is 1.13D

Explanation:

Given the data in the question;

Length = 2l

pressure drop in the first pipe is 1.657 times greater than it is for the second pipe.

Now, we know that for Laminar Flow;

V' = πD⁴ΔP / 128μL

where V'₁ = V'₂ and ΔP₁₋₂ = 1.657 ΔP₂₋₃

Hence,

V'₁ = πD⁴ΔP₁₋₂ / 128μL  = V'₃ = πD₃⁴ΔP₂₋₃ / 128μL

so

D₃ = D( ΔP₁₋₂ / ΔP₂₋₃ )^{\frac{1}{4}

we substitute

D₃ = D( 1.657 )^{\frac{1}{4}

D₃ = D( 1.134568 )

D₃ = 1.13D

Therefore, the diameter of the second pipe D₃ is 1.13D

8 0
3 years ago
Other questions:
  • Carbon dioxide contained in a piston–cylinder device is compressed from 0.3 to 0.1 m3. During the process, the pressure and volu
    9·1 answer
  • Which of the following manufacturing tools machines parts by moving the part into the cutting tool (instead of moving the cuttin
    13·1 answer
  • Three possible career opportunities in embedded systems engineering
    11·1 answer
  • The use of alcohol can cause
    6·2 answers
  • Which option distinguishes the step in the requirements engineering process described in the following scenario?
    9·2 answers
  • Who here likes to play project gotham racing?<br> will mark brainlyest
    8·2 answers
  • Can someone please answer this, it will be very appreciative
    6·1 answer
  • What is the physical mechanism that causes the friction factor to be higher in turbulent flow?
    13·1 answer
  • In approximately fifty words, explain what would be most significant for an architect about studying a modern painting composed
    5·1 answer
  • A pressure-temperature curve shows that pressure and temperature are ____ in a refrigeration system.
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!