Answer:
The pouring of the molten metal during casting is done very slowly hence the molten metal froze before reaching all parts of the mould cavity. also the early freezing can occur if the temperature of the molten metal was lower than the required temperature for casting
Explanation:
since the same components are being casted at other foundries and they don't have the defects ,
Hence the reason for the defects experienced by these components can be caused when the pouring of the molten metal during casting is done very slowly hence the molten metal froze before reaching all parts of the mould cavity. also the early freezing can occur if the temperature of the molten metal was lower than the required temperature for casting .
When the in-plane shear stress is at its highest, it is true that the normal stresses are equal.
Their combined value is σn+σt.
<h3>What is in-plane shear stress?</h3>
- 6.3 ksi is the maximum in-plane shear stress. 10.2 ksi is the maximum out-of-plane shear stress.
- By examining Mohr's circle, we may understand why out of plane shear stress is the highest.
- Maximum in-plane shear stress is indicated by the inner blue circle radius (6.3 ksi).
- Maximum shear stress planes are 45 degrees from the major planes.
- The principle stress is the highest stress that may be created in a plane, and the principal stress refers to the principal plane when shear stress is zero.
The complete question is:
What is true about the normal stresses when the in-plane shear stress is maximum? Select all that apply.
a) They are equal.
b) They are zero.
c) Their sum is equal to σn+σt.
d) They are maximum.
e) They are equal to shear stress.
To learn more about in-plane shear stress, refer to:
brainly.com/question/15517350
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Answer:
critical stress = 595 MPa
Explanation:
given data
fracture toughness = 74.6 MPa-
crack length = 10 mm
f = 1
solution
we know crack length = 10 mm
and crack length = 2a as given in figure attach
so 2a = 10
a = 5 mm
and now we get here with the help of plane strain condition , critical stress is express as
critical stress = ......................1
put here value and we get
critical stress =
critical stress = 595 MPa
so here stress is change by plane strain condition because when plate become thinner than condition change by plane strain to plain stress.
plain stress condition occur in thin body where stress through thickness not vary by the thinner section.
Answer:
Great question! Are you useing copper frige tubing if so>
Explanation:
if you are makeing a heater for a fire you are on the right path. Just slowly undo the tubbing. It hint here is slow. I have sometimes used a heat gun to slowly get it apart. Just heat it till in is soft enought to get un done. Then you can use it on a fire to heat water or what ever else you had in mind.