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3 years ago

Solve the following system of equations algebraically: x + 4y = 2 y = 2x + 14

Mathematics

2 answers:

loris [4]3 years ago

3 0

Answer:

x = -6

Step-by-step explanation:

You can insert the second equation in for the y-variable in the first equation

x + 4(2x+14) = 2

The next step is to distribute the 4

x + 8x + 56 = 2

Then we combine like terms

9x + 56 = 2

Subtract 56 from both sides

9x = -54

Divide by 9 on both sides

x = -6

Kruka [31]3 years ago

3 0

Answer:

x = - 6; y = 2

Step-by-step explanation:

{x + 4y = 2

{y = 2x + 14

x = 2 - 4y

y = 2x + 14

y = 2(2 - 4y) + 14

y = 4 - 8y + 14

y + 8y = 14 + 4

9y = 18

y = 18/9

y = 2

x = 2 - 4y

x = 2 - 4×2

x = 2 - 8

x = - 6

I hope I've helped you.

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Snezhnost [94]

Answer:

Step-by-step explanation:

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3 0

3 years ago

Find the solution of this system of equations. separate the x and y values.<br> x=2+y<br> -6x-6y=-12

Shkiper50 [21]

{x=2+y
{-6x-6y=-12

-6(2+y) -6y = -12
-12 - 6y - 6y = -12
-12y = -12 + 12
-12y = 0
y = 0

x = 2 + y = 2 + 0 = 2

Answer: x=2, y=0

8 0

3 years ago

Substitute the values for a, b, and c into b2 – 4ac to determine the discriminant. Which quadratic equations will have two real

hoa [83]

Answer: $0=2x^2-7x-9\\0=4x^2-3x-1\\0=x^2-2x-8$

Step-by-step explanation:

We know that the standard quadratic equation is ax^2+bx+c=0

Let's compare all the given equation to it and , find discriminant.

1. a=2, b= -7, c=-9

$b^2-4ac=(-7)^2-4(2)(-9)=49+72>0$

So it has 2 real number solutions.

2. a=1, b=-4, c=4

$b^2-4ac=(-4)^2-4(1)(4)=16-16=0$

So it has only 1 real number solution.

3. a=4, b=-3, c=-1

$b^2-4ac=(-3)^2-4(4)(-1)=9+16=25>0$

So it has 2 real number solutions.

4. a=1, b=-2, c=-8

$b^2-4ac=(-2)^2-4(1)(-8)=4+32=36>0$

So it has 2 real number solutions.

5. a=3, b=5, c=3

$b^2-4ac=(5)^2-4(3)(3)=25-36=-9$

Thus it does not has real solutions.

5 0

3 years ago

Read 2 more answers

Can someone please give me the answers to this? ... please ...

Gelneren [198K]

Step-by-step explanation:

the midpoint between 2 points (x1, y1) and (x2, y2) is simply ((x1+x2)/2, (y1+y2)/2).

so,

(9, 7) to (4, -3)

midpoint is ((9+4)/2, (7+ -3)/2) = (13/2, 4/2) = (6.5, 2)

(-7, -5) to (2, 1)

midpoint is ((-7+2)/2, (-5+1)/2) = (-5/2, -4/2) = (-2.5, -2)

now we have the midpoint and need the second point.

(4, 2) over (3, 4) to (x, y)

3 = (4 + x)/2

6 = 4 + x

x = 2

4 = (2 + y)/2

8 = 2 + y

y = 6

(-2, 1) over (-3, 2) to (x, y)

-3 = (-2 + x)/2

-6 = -2 + x

x = -4

2 = (1 + y)/2

4 = 1 + y

y = 3

5 0

2 years ago

Select the description that is true to the equation x + y =2<br><br>

lutik1710 [3]

Number one is correct

7 0

3 years ago