Question

Please help!! Thank you so much in advance :)

Answer 1

Answer:

Step-by-step explanation:

x = 1 - i sqrt(2) ^ y = 10 + i sqrt(2)

x = 1 + i sqrt(2) ^ y = 10 - i sqrt(2)

Answer 2

Answer:

Step-by-step explanation:

y = 11 - x  ----------(I)

y  = 2x² - 4x + 6 -----------(II)

Substitute y = 11- x in (II)

11 - x = 2x² - 4x + 6

0 = 2x² - 4x + x + 6 - 11

0 = 2x² - 3x - 5

2x² - 3x  - 5 = 0

Sum = -3

Product = -10

Factors = -5 , 2

2x² - 5x + 2x - 5 = 0

x(2x - 5) + (2x - 5) = 0

(2x -5 )(x +1)=0

2x - 5 = 0  ; x + 1 = 0

2x = 5      ; x = -1

  x = 5/2

When x = -1   ;  y = 11 - (-1) = 11 + 1 = 12

$When x = \dfrac{5}{2} ; y = 11- \dfrac{5}{2}= \dfrac{22}{2}- \dfrac{5}{2}= \dfrac{17}{2}$

Solution:  (-1 , 12)  and (5/2 , 17/2)