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aev [14]
3 years ago
7

The final velocity V of an object

Mathematics
2 answers:
defon3 years ago
8 0
Final velocity (v) of an object equals initial velocity (u) of that object plus acceleration a Final velocity (v) of an object equals initial velocity (u) of that object plus acceleration (a) of the object times the elapsed time (t) from u to v. of the object times the elapsed time t from u to v
Alekssandra [29.7K]3 years ago
7 0

Answer:

The final velocity, V, of an object under constant acceleration can be found using the formula V2=v2+2as , where v is the initial velocity in meters per second, a is acceleration in meters per second, and s is the distance in meters.

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Use the pie chart below to answer the following question.
Airida [17]

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Find the scale factor of the smaller figure to the larger figure
3241004551 [841]
(smaller length measure) to (larger length measure)
3 to 9 or 6 to 18
reduces to 1 to 3 or \frac{1}{3}
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blagie [28]
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2 years ago
An equilateral triangle has a side length of 6. What is the height of the triangle?
vlabodo [156]
Since the height of an equilateral triangle in terms of its side s is s√3/2, the height of the triangle is 6√3/2 = 3√3 and so the area is (1/2)(6)(3√3) = 9√3. 

<span>If we draw a horizontal line a height of h from the base of the triangle, the region is split into two regions: the lower region consisting of a trapezoid of height h and the upper region consisting of a triangle of height 3√3 - h. </span>

<span>Since the upper triangle and the triangle itself are similar triangles, the base and height are proportional. If we let x denote the base of the length of the upper triangle, we have: </span>

<span>(S. of small triangle)/(S. of big triangle) = (Ht. of small triangle)/(Ht. of big triangle) </span>
<span>==> x/6 = (3√3 - h)/(3√3) </span>
<span>==> x = (6√3 - 2h)/√3 </span>

<span>Thus, the area of the upper triangle is: </span>

<span>A = (1/2)[(6√3 - 2h)/√3](3√3 - h) = [(6√3 - 2h)(3√3 - h)]/(2√3). </span>
<span>(Made a dumb mistake about the height here for some reason) </span>

<span>Since we require that the area of this triangle is to be half of the total area (9√3/2), we need to solve: </span>

<span>[(6√3 - 2h)(3√3 - h)]/(2√3) = 9√3/2 </span>
<span>==> (6√3 - 2h)(3√3 - h) = 27 </span>
<span>==> 54 - 6h√3 - 6h√3 + 2h^2 = 27 </span>
<span>==> 2h^2 - 12h√3 + 27 = 0. </span>

<span>Solving with the Quadratic Formula gives: </span>

<span>h = (6√3 + 3√6)/2 ≈ 8.87 units and h = (6√3 - 3√6)/2 ≈ 1.52 units. </span>

<span>Since h = (6√3 + 3√6)/2 would place the line outside of the triangle, we pick h = (6√3 - 3√6)/2. </span>

<span>Therefore, the line should be ==> (6√3 - 3√6)/2 units from the base. </span>

<span>I hope this helps! ^^ Brainliest Please?</span><span>
</span>
5 0
3 years ago
Read 2 more answers
A machine packs at a constant rate of 2/3 of a box every 1/2 minuet. What’s is the number of boxes per minute that’s the machine
lions [1.4K]
For this case what we can do is the following rule of three:
 2/3 of a box ------> 1/2 minutes
 x of a box ---------> 1 minute
 Clearing x we have:
 x = (1 / (1/2)) * (2/3)
 Rewriting:
 x = 2 * (2/3)
 x = 4/3
 Answer:
 the number of boxes per minute that the machine packs is:
 x = 4/3
4 0
3 years ago
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