Answer:
A. 1.6 × 105 joules
Explanation:
As per the question, the data given in the question is as follows
Number of masses = 2
Each weightage =
Speed = 12.5 meters/ second
Based on the above information, the approximate kinetic energy after the collision is
A perfectly elastic collision is described as one where the collision does not cause any loss of kinetic energy.
So we sum the kinetic energy of each kind of system which is given below:
Kinetic energy is
= 156250 J
Answer: 3071.79 m/s
Explanation:
Approaching satellite's orbit around the Earth to a circular orbit, we can use the equation of velocity in the case of uniform circular motion:
(1)
Where:
is the velocity of the satellite
is the Gravitational Constant
is the mass of the Earth
is the radius of the orbit
Now, if we want the satellite to move in a <u>geosynchronous orbit</u>, it needs to travel at a specific orbiting radius and period to fulfill this condition. This means the satellite's orbital period must match Earth's rotation on its axis, which takes one sidereal day ( approximately 24 h).
So, if the satellite travels one complete circle in a period , its velocity is also expressed as:
(2)
Where
Combining (1) and (2):
(3)
Isolating :
(4)
(5)
Substituting (5) in (1):
(6)
Finally:
.6(9.81)(3)
=17.65
18 J
2 significant figures
Answer:
240cm
Explanation:
Speed = 6cm/s
Time = 40 seconds
Speed= distance/time
6cm/s = distance/40seconds
Distance = 6×40
Distance = 240cm
Hence, in 40 seconds, the ball must have rolled the distance of 240cm