The tensile stress of the wire supporting 2 kg mass is determined as 6.1 x 10⁷ N/m².
<h3>
Tensile stress of the wire</h3>
The tensile stress of the wire is calculated as follows;
σ = F/A
where;
A = πr² = πD²/4
where;
A = π x (0.64 x 10⁻³)²/4
A = 3.22 x 10⁻⁷ m²
σ = F/A = (mg)/A = (2 x 9.8)/( 3.22 x 10⁻⁷)
σ = 6.1 x 10⁷ N/m²
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Answer:
a) N = 343 [N]
Explanation:
We must remember Newton's third law, which tells us that the force acting on a body is equal to the normal reaction force of equal magnitude but acting in the opposite direction.
where:
m = mass = 35 [kg]
g = gravity acceleration = 9.81 [m/s²]
![N = 35*9.8\\N= 343 [N]](https://tex.z-dn.net/?f=N%20%3D%2035%2A9.8%5C%5CN%3D%20343%20%5BN%5D)
Answer:
Gravity
Explanation:
The Hubble is continually attracted to the earth due to the action of gravity. Therefore, it is thanks to gravity that the space telescope is kept in orbit. Without him, the direct motion generated by inertia would take him out of course. Gravity slows it down and keeps it in the curved path of its orbit around the Earth.
Answer:
Explanation:
Given that,
Mass per unit length is
μ = 4.87g/cm
μ=4.87g/cm × 1kg/1000g × 100cm/m
μ = 0.487kg/m
Tension
τ = 16.7N
Amplitude
A = 0.101mm
Frequency
f = 71 Hz
The wave is traveling in the negative direction
Given the wave form
y(x,t) = ym• Sin(kx + ωt)
A. Find ym?
ym is the amplitude of the waveform and it is given as
ym = A = 0.101mm
ym = 0.101mm
B. Find k?
k is the wavenumber and it can be determined using
k = 2π / λ
Then, we need to calculate the wavelength λ using
V = fλ
Then, λ = V/f
We have the frequency but we don't have the velocity, then we need to calculate the velocity using
v = √(τ/μ)
v = √(16.7/0.487)
v = 34.29
v = 5.86 m/s
Then, we can know the wavelength
λ = V/f = 5.86 / 71
λ = 0.0825 m
So, we can know the wavenumber
k = 2π/λ
k = 2π / 0.0825
k = 76.18 rad/m
C. Find ω?
This is the angular frequency and it can be determined using
ω = 2πf
ω = 2π × 71
ω = +446.11 rad/s
D. The angular frequency is positive (+) because the direction of propagation of wave is in the negative direction of x
Red is the lowest because it has the shortest wavelengths
