1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
otez555 [7]
3 years ago
8

Can u guys please help me​

Mathematics
1 answer:
maw [93]3 years ago
6 0

Answer:

a. 3.4m

b. 12.2m

Step-by-step explanation:

SOH CAH TOA

Sin QPS=\frac{Opposite}{hypotenuse}

sin 15° = \frac{QS}{PQ}

QS= sin 15° * PQ

QS = 0.2588 * 12.6 = 3.36088 ≈ 3.4m

a. The length of QS = 3.4m

b. cos QPS=\frac{Adjacent}{Hypotenuse}

Cos 15° = \frac{PS}{PQ}

PS = Cos 15° * PQ

PS = O.9659 * 12.6 = 12. 17034 ≈ 12.2m

The length of PS = 12.2m

You might be interested in
a real estate company sells 8 houses per month write an equation to find the total number of houses h sold in any number of mont
Verdich [7]
H=8x,so a real estates will sell 120 houses in 15 months. Hope it help!
3 0
3 years ago
A total of 336 tickets were sold for the school play. They were either adult tickets or student tickets. The number of student t
wolverine [178]

Let x = number of adult tickets

Let 2x = number of student tickets.


So, x + 2x = 336

3x = 336

x = 112


They sold 112 adult tickets.

8 0
3 years ago
Read 2 more answers
Please help me with questions 13-22!! I know I already answered 14 but if it is wrong please tell me!!! I don't have much time!!
neonofarm [45]

Answer:

13. no solution

15. 3

16. 2

17. 5

18. -8

19. -7

20. 6

21. -5

22. -7

3 0
4 years ago
Stan and hilda can mow the lawn in 35 min if they work together. if hilda works twice as fast as stan, how long would it take st
mash [69]
<span>105 minutes "Stan and Hilda can mow the lawn in 35 min" 35 = 1/(S + H) "Hilda works twice as fast as Stan" H = 2S "how long would it take Stan to mow the lawn alone?" T = 1/S First, let's determine what S is, so 35 = 1/(S + H) Substitute 2S for H 35 = 1/(S + 2S) Solve for S 35 = 1/(3S) 35(3S) = 1) 105S = 1 S = 1/105 Now solve T = 1/S with S = 1/105 T = 1/S T = 1/(1/105) T = 1/1 / 1/105 T = 1/1 * 105/1 T = 105 So it will take Stan 105 minutes to mow the lawn alone.</span>
5 0
3 years ago
Estion 4
Sunny_sXe [5.5K]

Answer:

Check Explanation

Step-by-step explanation:

Sale price = GHS80 per unit from first week of December to first week of January.

And at a reduced price of 30% from second week of January to the last week of January.

So, sales price for the second period = 70% × 80 = GHS56

To now find the profits for each of the purchase alternatives, we need to calculate the expected total demand

Expected demand units = (Demand × Probability)

First Period

Demand Probability | Expected demand units

500 0.1 | 50

600 0.3 | 180

750 0.4 | 300

850 0.2 | 170

Second period

Demand Probability | Expected demand units

320 0.5 | 160

180 0.3 | 54

130 0.2 | 26

Total expected demand units for first period = 50 + 180 + 300 + 170 = 700

Total expected demand units for second period = 160 + 54 + 26 = 240

i) When a pack of 600 products only is ordered, it is evident that it will cater for only the first period.

Expected Profit = (Expected sales it can cater for) - (Price of one pack of 600 products)

Expected sales it can cater for = 600 × 80 = GHS 48,000

Expected price of one pack of 600 products = 600 × 60 = GHS 36,000

Expected profit = 48000 - 36000 = GHS 12,000

ii) When a pack of 800 products only is ordered, it is evident that it will cater for the entire first period (700) and 100 from the second period.

Expected Profit = (Expected sales it can cater for) - (Price of one pack of 800 products)

Expected sales it can cater for = (700 × 80) + (100 × 56) = 56,000 + 5,600 = GHS 61,600

Expected price of one pack of 800 products = 800 × 57 = GHS 45,600

Expected profit = 61600 - 45600 = GHS 16,000

iii) When a pack of 1000 products only is ordered, it is evident that it will cater for the entire period, 700 and 240.

Expected Profit = (Expected sales it can cater for) - (Price of one pack of 1000 products)

Expected sales it can cater for = (700 × 80) + (240 × 56) = 56,000 + 13,440 = GHS 69,440

Expected price of one pack of 100 products = 1000 × 52 = GHS 52,000

Expected profit = 69440 - 52000 = GHS 17,440

iv) To do this, we first assume that

- the probabilities provided are very correct.

- the products are sold on a first come first serve basis

- the profits per unit for each period is calculated too.

Profit per product in this case = (16000/800) = GHS 20

For the first period

Expected profit = (700 × 80) - (700 × 57) = GHS 16,100

Average profit per unit = (16100/700) = GHS 23

For the second period

Expected profit = (100 × 56) - (100 × 57) = - GHS 100

Average profit per unit = (-100/100) = -GHS 1

Standard deviation = √[Σ(x - xbar)²/N]

Σ(x - xbar)² = [700 × (23-20)²] + [100 × (-1-20)²]

= 6300 + 44,100 = 50,400

N = 800

Standard deviation per unit = √(50400/800) = GHS 7.94

Variance per unit = (standard deviation per unit)² = (7.94)² = 63.

Variance on 800 units = 800 (1² × 63) = 800 × 63 = 50,400

Standard deviation on profits of 800 units = √(50400) = GHS 224.5

v) With the same assumptions as in (iv), but now, we include the Profit (or more appropriately, the loss from unsold units of products)

Profit per product in this case = (17440/1000) = GHS 17.44

For the first period

Expected profit = (700 × 80) - (700 × 52) = GHS 19,600

Average profit per unit = (19600/700) = GHS 28

For the second period

Expected profit = (240 × 56) - (240 × 52) = - GHS 960

Average profit per unit = (960/240) = GHS 4

The expected unsold products = 1000 - 940 = 60

Profit on those unsold products = 0 - (60 × 52) = -GHS 3,120

Profit per unit = (-3120/60) = - GHS 52

Standard deviation = √[Σ(x - xbar)²/N]

Σ(x - xbar)² = [700 × (28-17.44)²] + [240 × (4-17.44)²] + [60 × (-52-17.44)²]

= 78,059.52 + 43,352.064 + 289,314.816 = 410,726.4

N = 1000

Standard deviation per unit = √(410,726.4/1000) = GHS 20.27

Variance per unit = (standard deviation per unit)² = (20.27)² = 410.7264

Variance on 1000 units = 1000 (1² × 410.7264) = 800 × 410.7264 = 410,726.4

Standard deviation on profits of 1000 units = √(410,726.4) = GHS 640.88

vi) The standard deviation on profits show how much the real profits can range below or abobe the expected profit. That is, the standard deviation basically represents how big the risks or rewards can get.

A larger standard deviation will indicate a higher risk in case of loss and a higher reward in case of profits.

The option with the lower risk is the option with the lower standard deviation.

Hence, a pack of 800 products should be ordered instead of a pack of 1000 products as it has a lower standard deviation and hence, a lower risk attached to it thereby minimizing the risk.

Hope this Helps!!!

5 0
4 years ago
Other questions:
  • Sue buys a certain brand of cereal that costs $12 per box. Sue changes to a super-saving brand of the same size. The equation sh
    5·1 answer
  • I,ii,iii,iiii,iiiii what is the twentieth term?
    13·2 answers
  • Beth won 86 pieces of gum playing hoops at her school's game night. Later, she gave three to each of her friends. She only has 2
    5·1 answer
  • There are 40 students in an elementary statistics class. On the basis of years of experience, the instructor knows that the time
    14·1 answer
  • Un camión pesa 875 kg la diferencia entre el peso del camión vacío y el peso de la carga que lleve no debe ser inferior a 415 kg
    13·1 answer
  • Please will give brainliest and thanks please please
    11·2 answers
  • Which equation represents a nonlinear function?
    8·1 answer
  • What is least too greatest?<br> 0.65,0.59,3/5
    13·2 answers
  • What percent of the current number of states had joined<br> the United States by the year 1863?
    6·1 answer
  • A circle has a area of 49 pie cm2 work out its radius
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!