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3 years ago

How do you solve 57.82 divided by 0.784

Mathematics

1 answer:

lys-0071 [83]3 years ago

4 0

Answer:

Step By Step Explanation!-

57.82

0.784

______

57820

784

______

73.75

57.82

0.784

_____

73.75

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The combined average weight of an okapi and a llama is 450450 kilograms. The average weight of 33 llamas is 190190 kilograms mor

Nataliya [291]

Answer:

Okapi 290 kg

Llama 160 kg

Step-by-step explanation:

Let weight of each llama be $l$

Let weight of each okapi be $o$

Given, combined weight of 1 okapi and 1 llama is 450, we can write:

$l+o=450$

Also, average weight of 3 llama is 190 more than the average weight of 1 okapi, thus we can write:

$3l-190=o$

Now, substituting 2nd equation into 1st equation, we can solve for weight of 1 llama:

$l+o=450\\l+(3l-190)=450\\l+3l-190=450\\4l=450+190\\4l=640\\l=\frac{640}{4}=160$

Each llama weights 160 kg, now using this and plugging into 2nd equation, we get weight of 1 okapi to be:

$o=3l-190\\o=3(160)-190\\o=290$

Each okapi weigh 290 kg

5 0

4 years ago

What is the answer to this proportion question? 5m-3/63 = 9/21

VMariaS [17]

Answer:

Step-by-step explanation:

21(5m - 3) = 63*9

105m - 63 = 567

105m = 630

m = 6

4 0

2 years ago

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Simplify 18 - 2[ x + ( x - 5)]. 8 - 4 x 28 - 4 x 28 - 2 x

Arisa [49]

The answer for this question is 28-4x

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3 years ago

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2. The National Safety Council routinely analyzes the benefit of seat belt use on driver safety. Their data showed that among 28

JulijaS [17]

Answer:

We conclude that there is difference in the proportion of deaths between the 2 groups.

Step-by-step explanation:

We are given that among 2823 drivers not wearing seat belts, 31 died as a result of injuries, and among 7765 drivers wearing seat belts 16 were killed.

Let $p_1$ = proportion of deaths when drivers were not wearing seat belts.

$p_2$ = proportion of deaths when drivers were wearing seat belts.

So, Null Hypothesis, $H_0$ : $p_1=p_2$ {means that there is no difference in the proportion of deaths between the 2 groups}

Alternate Hypothesis, $H_A$ : $p_1\neq p_2$ {means that there is difference in the proportion of deaths between the 2 groups}

The test statistics that would be used here Two-sample z test for proportions;

T.S. = $\frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2} } }$ ~ N(0,1)

where, $\hat p_1$ = sample proportion of deaths when drivers were not wearing seat belts = $\frac{31}{2823}$ = 0.011

$\hat p_2$ = sample proportion of deaths when drivers were wearing seat belts = $\frac{16}{7765}$ = 0.002

$n_1$ = sample of drivers not wearing seat belts = 2823

$n_2$ = sample of drivers wearing seat belts = 7765

So, the test statistics = $\frac{(0.011-0.002)-(0)}{\sqrt{\frac{0.011(1-0.011)}{2823}+\frac{0.002(1-0.002)}{7765} } }$

= 4.438

The value of z test statistics is 4.438.

Now, at 5% significance level the z table gives critical values of -1.96 and 1.96 for two-tailed test.

Since our test statistic doesn't lie within the range of critical values of z, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that there is difference in the proportion of deaths between the 2 groups.

Also, Margin of error (E) = $1.96 \times \sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2} }$

= $1.96 \times \sqrt{\frac{0.011(1-0.011)}{2823}+\frac{0.002(1-0.002)}{7765} }$

= 0.00397

5 0

3 years ago

What is the total monthly payment for this mortgage? Principal Per Month $750 Interest Per Month $120 Property Tax Per Year 0.5

m_a_m_a [10]

Its $1,011.66. .5% of 140000 is 700, you have to divide by 12 to get tax for one month. which is 58.333. same with home insurance 460/12 which is 38.33. let's add them. 750+120+58.33+38.33+45= 1011.66.

5 0

4 years ago