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agasfer [191]
3 years ago
12

7 3 If you were to graph a line with a slope of 3/2 that intercepts the y-axis at -2 on the coordinate plane, one point on that

line would have a y coordinate of 4 with an x coordinate of what number?​
Mathematics
1 answer:
pychu [463]3 years ago
3 0

Answer:

4

Step-by-step explanation:

Make a graph.

Start at negative 2 because that's the y intercept. Remember that a minus sign in front of the y intercept just means it's negative.

The slope is basically the rise over the run. How much you go UP divided by how much you run. Since the slope is 3/2, we go up 3 and right 2.

Keep making points and you get 4

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\sf{ \purple{ \boxed{\bold{m =  -  \dfrac{7}{3} }}}}

\\

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We are given the points \sf{P_1(\overbrace{ \blue{8}}^{\blue{x_1}} ,\underbrace{\orange{-8}}_{ \orange{y_1}}) \: and \: P_2(\overbrace{ \green{5}}^{\green{x_2}} ,\underbrace{\red{-1}}_{\red{y_2} })} . To find the slope \sf{\purple{m}} of such a line, we use the slope formula which is the following:

\sf{ \purple{m} }=  \dfrac{\Delta y}{\Delta x}  =  \dfrac{ \red{y_2} - \orange{y_1}}{ \green{x_2 }- \blue{x_1}}

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⇢Now, by plugging in our values, we get :

\sf{ \purple{m}} =  \dfrac{ \red{ - 1} -  \orange{( - 8)}}{ \green{5} \:   -  \:  \blue{8}}  =  \dfrac{ \:  \: 7 \: }{ -  3 \: }  \\  \\  \implies \sf{ \purple{ \boxed{m =  -  \dfrac{7}{3} }}}

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