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agasfer [191]
2 years ago
12

7 3 If you were to graph a line with a slope of 3/2 that intercepts the y-axis at -2 on the coordinate plane, one point on that

line would have a y coordinate of 4 with an x coordinate of what number?​
Mathematics
1 answer:
pychu [463]2 years ago
3 0

Answer:

4

Step-by-step explanation:

Make a graph.

Start at negative 2 because that's the y intercept. Remember that a minus sign in front of the y intercept just means it's negative.

The slope is basically the rise over the run. How much you go UP divided by how much you run. Since the slope is 3/2, we go up 3 and right 2.

Keep making points and you get 4

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Reiko takes 2 coins at random from the 3 quarters, 5 dimes, and 2 nickels in her pocket. three coins are tossed. what is the pro
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3 years ago
<img src="https://tex.z-dn.net/?f=9%5C%3A%20%20%5C%3A%20%20%5Cfrac%7B%20%5Csin%28%20%5Ctheta%29%20%7D%7B1%20%2B%20%20%5Ccos%28%2
PIT_PIT [208]

Option (b) is your correct answer.

Step-by-step explanation:

\large\underline{\sf{Solution-}}

Given Trigonometric expression is

\rm :\longmapsto\:\dfrac{sin\theta }{1 + cos\theta }

So, on rationalizing the denominator, we get

\rm \:  =  \: \dfrac{sin\theta }{1 + cos\theta }  \times \dfrac{1 - cos\theta }{1 - cos\theta }

We know,

\purple{\rm :\longmapsto\:\boxed{\tt{ (x + y)(x - y) =  {x}^{2} -  {y}^{2} \: }}}

So, using this, we get

\rm \:  =  \: \dfrac{sin\theta (1  -  cos\theta )}{1 -  {cos}^{2}\theta  }

We know,

\purple{\rm :\longmapsto\:\boxed{\tt{  {sin}^{2}x +  {cos}^{2}x = 1}}}

So, using this identity, we get

\rm \:  =  \: \dfrac{sin\theta (1 -  cos\theta )}{{sin}^{2}\theta  }

\rm \:  =  \: \dfrac{1 - cos\theta }{sin\theta }

<u>Hence, </u>

\\ \red{\rm\implies \:\boxed{\tt{ \rm \:\dfrac{sin\theta }{1 + cos\theta }   =  \: \dfrac{1 - cos\theta }{sin\theta } }}} \\

3 0
2 years ago
Read 2 more answers
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