Answer:
Molarity = 0.5 M
Explanation:
Given data:
Mass of NaCl = 2.7 g
Volume = 100 mL(100×10⁻³L)
Molarity of solution = ?
Solution:
Formula:
Molarity = number of moles / volume in litter
Number of moles:
Number of moles = mass/ molar mass
Number of moles = 2.7 g/ 58.5 g/mol
Number of moles = 0.05 mol
Molarity = number of moles / volume in litte
Molarity = 0.05 mol / 100×10⁻³L
Molarity = 0.5 M
Yes, you add water to Campbell's Chicken Noodle Condensed Soup because "condensed" soup is more concentrated and has less water in it. Adding water will dilute the soup mixture to the desired consistency.
Answer:
Gram atomic mass of an element can be defined as the mass of one mole of atoms of a particular element. It is numerically equivalent to the value of the element's atomic mass unit but has its unit in grams.
The law of conservation of mass states that the mass of a system must remain constant everytime, it can neither be created or destroyed. This means the number of atoms of each element on reactant side must equal the number of atoms of each element on product side.
First we figure out the chemical formula for each compound by taking advantage of oxidation states which are able to tell us whether an element will lose or gain an electron
Strontium hydroxide?
Sr is an alkaline earth metal which has 2 valence electrons that when both are lost it has an oxidation state of +2. Since we know the hydroxide ion has a charge of -1,
, Then two
are needed to form compound, hence we have 
zirconium (I) perchlorate?
The oxidation state of zirconium is +1 since it is stated that we have zirconium(I). Converserly, perchlorate has a -1 charge which further proves that zirconium has a +1 oxidation state
The product would have a strontium diperchlorate because we know from earlier that Sr has a +2 oxidation state, and we would also have ZrOH because Zr has a +1 oxidation state and
has a -1 charge
The unbalanced equation with all chemicals formulas would be

Using the law of conservation of mass, it is clear that there is 1 molecule of
on reactant side as compared to 2 molecules of
on product side. On the other hand, the are 2 molecules of
on reactant side and 1 molecule of
on product side. To balance we add a coefficient of 2 on
and a coefficient of 2 on ZrOH,
.