A quadrilateral has no pairs of parallel sides

Mathematics

1 answer:

shutvik [7]3 years ago

5 0

Answer:kite and rhombus

Step-by-step explanation:

Kite and rhombus are quadrilaterals that doesn't have parallel sides

You might be interested in

Solve 2csc^2x-2cscx-1=0 for 0° ≤ x ≤ 360°

umka21 [38]

Answer:

Step-by-step explanation:

2 csc²x-2 csc x-1=0

$\frac{2}{sin^2x} -\frac{2}{sin x} -1=0\\multiply~by~sin^2x\\2-2sin~x-sin^2x=0\\sin^2x+2sinx-2=0\\sin ~x=\frac{-2 \pm\sqrt{2^2-4*1*(-2)} }{2*1} \\=\frac{-2 \pm\sqrt{4+8} }{2} \\=\frac{-2 \pm\sqrt{4*3} }{2} \\=\frac{-2 \pm2\sqrt{3} }{2} \\=-1\pm\sqrt{3} \\|sin~x| \le ~1\\so~sin~x=-1+\sqrt{3} \\sin~x=\sqrt{3} -1\\x=sin^{-1}(\sqrt{3} -1) \approx 47.06^\circ,180-47.06\\or~x=47.06^\circ,132.94^\circ$

6 0

3 years ago

Janet has 120 dollars,. if she saves 20 dollars per week, in how many days will she have 500?

GrogVix [38]

After 28 days she will have 200. every 28 days she saves 80 dollars and after 112 she will have saved 320. She will then be at 460 and need 40 more dollars which is 14 days, and 112 plus 14 is 126 days. Hope that helped

4 0

3 years ago

Explain why if a runner completes a 6.2â-mi race in 32 âmin, then he must have been running at exactly 11 âmi/hr at least twice

MA_775_DIABLO [31]

Answer:

Accelerating to top speed, deaccelerating to finish line.

Step-by-step explanation:

If the runner kept a constant speed of 11 mph for the whole duration of his run (32 minutes), the distance he would have covered is:

$d=11*\frac{32}{60}\\d= 5.87\ mi$

This means that, in order to run the full 6.2 miles, the runner needs to reach a speed over 11 mph. Assume he starts from rest, while accelerating the runner reaches, and the surpasses, the 11 mph mark. Since his speed at the finish line is zero, the runner has to deaccelerate from his current running speed (which should be higher than 11 mph), passing through 11 mph and reaching zero at the finish line.