All we have to do is set this up!
we know that all he practiced altogether for 15 and 1/3 hours
so lets put that down so far
1
15 ----- =
3
and he says that the first week he played 6 and 1/4 hours on the first week
now lets add that
1 1
15 ----- = 6 ----- +
<span> 3 4
</span>now we also know that he played 4 and 2/3 hours on the first week
now lets add that
1 1 2
15 ----- = 6 ----- + 4 ----- +
<span> 3 4 3
</span>we arent finished yet!
now the third week we dont know how long he played so we are going to put x in its place
1 1 2
15 ----- = 6 ----- + 4 ----- + x
<span> 3 4 3
</span>and there is your answer! finally...
hope this helps:) MARK AS BRAINLIEST!!!
:D
So b/10 has to be -1, that means b is -10
I thank the answer is B) 23
Answer:
x=9
Step-by-step explanation:
Use the intersecting chord theorem:
RE*ET = UE*ES
Substitute values
21 (2x+2) = 30 (x+5)
Expand:
42x+42 = 30x + 150
transpose and simplify
42x-30x = 150 - 42
12x = 108
x = 9
1. Given a group of n people. There are C(n, r) ways of forming groups of r out of n.
2. Where C(n, r)=

3. For example, given {Andy, John, Julia}. We want to pick 2 people to give a gift: we can pick {(Andy, John), (Andy, Julia), (John, Julia)}, so there are 3 ways. So we can list and count.
4. Or we could do this with the formula C(3, 2)=

5. C(8, 6)=

So there are C(8,6)=28 ways of chosing 6 out of 8 people to form the subcommittees. <span />