Answer:
Kindly check explanation
Step-by-step explanation:
Dr. Jones conclusion was based on probability which measures the degree of likelihood of an occurrence or event. In his experiment, the result could be interpreted using point estimate to mean that ; 78/100 = 0.78 or 78% of those who drank while pregnant has problem with attention while only 29/100 = 0.29 or 29% of those who did not drink.
This conclusion means that pregnant women who drink have a higher likelihood of giving birth to a child with attention problem than pregnant women who do not drink. Hence, the fact that someone who drank gave birth to a perfectly healthy child does not discredit or annull Dr. Jones study.
Answer:
x=6
Step-by-step explanation:
-3x=-2x-6
-3x+2x=-6
-x=-6
x=6
Irregular hexagon/polygon
Answer:
First Equation: 6a-23
Second Equation: 5a-20
Step-by-step explanation:
So, I think you want me to answer part 2...
For the first equation, we can see that the denominator stays the exact same, meaning the numerator will also not change.
For the second equation, we can see the denominator changed from a-3 to 5a-15. The denominator was simply multiplied by 5. Since the denominator was multiplied by five we must multiply the numerator by five as well.
5(a-4)
5a-20
Hope this helps :)
Answer:
(E) 0.71
Step-by-step explanation:
Let's call A the event that a student has GPA of 3.5 or better, A' the event that a student has GPA lower than 3.5, B the event that a student is enrolled in at least one AP class and B' the event that a student is not taking any AP class.
So, the probability that the student has a GPA lower than 3.5 and is not taking any AP classes is calculated as:
P(A'∩B') = 1 - P(A∪B)
it means that the students that have a GPA lower than 3.5 and are not taking any AP classes are the complement of the students that have a GPA of 3.5 of better or are enrolled in at least one AP class.
Therefore, P(A∪B) is equal to:
P(A∪B) = P(A) + P(B) - P(A∩B)
Where the probability P(A) that a student has GPA of 3.5 or better is 0.25, the probability P(B) that a student is enrolled in at least one AP class is 0.16 and the probability P(A∩B) that a student has a GPA of 3.5 or better and is enrolled in at least one AP class is 0.12
So, P(A∪B) is equal to:
P(A∪B) = P(A) + P(B) - P(A∩B)
P(A∪B) = 0.25 + 0.16 - 0.12
P(A∪B) = 0.29
Finally, P(A'∩B') is equal to:
P(A'∩B') = 1 - P(A∪B)
P(A'∩B') = 1 - 0.29
P(A'∩B') = 0.71
