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3 years ago

Find the value of c. 16 = 4 - 3c

Mathematics

2 answers:

postnew [5]3 years ago

8 0

C = -4
16= 4- 3(-4)
16= 4 + 12
16=16

dybincka [34]3 years ago

6 0

Answer:

c = -4

Step-by-step explanation:

16 = 4 - 3c

subtract 4 from each side

16-4 = 4-4 - 3c

12 = -3c

Divide each side by -3

12/-3 = -3c/-3

-4 =c

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Step-by-step explanation:

Let the vertex A has coordinates $(x_A,y_A)$

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Vectors AC and AC' are perpendicular, then

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Now, solve the system of two equations:

$\left\{\begin{array}{l}(2-x_A)(-2-x_A)+(6-y_A)(2-y_A)=0\\ \\(4-x_A)(1-x_A)+(3-y_A)(4-y_A)=0\end{array}\right.\\ \\\left\{\begin{array}{l}-4-2x_A+2x_A+x_A^2+12-6y_A-2y_A+y^2_A=0\\ \\4-4x_A-x_A+x_A^2+12-3y_A-4y_A+y_A^2=0\end{array}\right.\\ \\\left\{\begin{array}{l}x_A^2+y_A^2-8y_A+8=0\\ \\x_A^2+y_A^2-5x_A-7y_A+16=0\end{array}\right.$

Subtract these two equations:

$5x_A-y_A-8=0\Rightarrow y_A=5x_A-8$

Substitute it into the first equation:

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