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3 years ago

Two positive numbers have a difference of 17. The larger number is one more than twice the smaller. Find the two numbers.

Mathematics

1 answer:

frosja888 [35]3 years ago

7 0

$(2x+1)-x=17\\
x+1=17\\
x=16\\
plug~16~in~for~x.\\The~bigger~number~is~ 2(16)+1=33, \\~the~smaller~number~is~16.$

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Going top to bottom label them as A, B, C, and D

Ket [755]

I hope this helps you

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3 years ago

D is the wrong answer please help :(

Stella [2.4K]

This can be solved by Newton's binomial formula

Tk+1 = (n k) a∧(n-k) b∧k k+1=7 => k=6, n=11 , a=-3x and b=-2y

T7= (11 6) (-3x)∧(11-6) (-2y)∧6 = (11*10*9*8*7)/(1*2*3*4*5) (-3x)∧5 (-2y)∧6

T7= 462 (-3x)∧5 (-2y)∧6

The correct answer is A.

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2 years ago

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How to solve 2x(x+3)=2x^2+15

Travka [436]

Answer: x = 5/2 = 2.5

Step-by-step explanation:

Given expression

2x (x + 3) = 2x² + 15

Expand parentheses and apply the distributive property

2x · x + 2x · 3 = 2x² + 15

2x² + 6x = 2x² + 15

Subtract 2x² on both sides

2x² + 6x - 2x² = 2x² + 15 - 2x²

6x = 15

Divide 6 on both sides

6x / 6 = 15 / 6

x = 15/6

$\boxed{x=\frac{5}{2} }$

Hope this helps!! :)

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3 years ago

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GCF of 20 and another number is four. Which of these could be the other number

Nina [5.8K]

Answer:

Step-by-step explanation:

4 x 9=32

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3 years ago

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Dave has 10 poker chips, 6 of which are red and the other 4 of which are white. Dave likes to stack his chips and flip them over

Marina86 [1]

The number of 10 chips stacks that Dave can make if two stacks are not considered distinct is 110.

The solution

To get the symmetric stacks, one has to subtract the symmetric stacks to know the ones that are asymmetric.

The symmetric are flipped. Given that they are double counted what we have to do is to divide through by 2.

6/2 = 3

10/2 = 5

4/2 = 2

1/2(10C6) - (5C3) + (5C3)

0.5(210-10+10)

= 110

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2 years ago