Question

Which triangle is similar to △ABC if sin(A)=1/4, cos(A)=√15/4, and tan(A)=1/√15?

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

(D)  

Step-by-step explanation:

The given triangle ABC has sinA=$\frac{1}{4}$, cosA=$\frac{\sqrt{15}}{4}$ and tanA=$\frac{1}{\sqrt{15}}$.

From the given options, option D is correct because, SinX=$\frac{6}{24}=\frac{1}{4}$,

cosX=$\frac{6\sqrt{15}}{24}=\frac{\sqrt{15}}{4}$ and

tanX=$\frac{6}{6\sqrt{15}}=\frac{1}{\sqrt{15}}$

Since, the values of sin, cos and tan of triangle XYZ are similar to teh values of triangle ABC, therefore triangle XYZ is similar to triangle ABC.