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Veronika [31]
3 years ago
8

Hi, I need help pls! (screenshots included)

Mathematics
1 answer:
mestny [16]3 years ago
5 0

8. a = s*s

144 = s^{2}

\sqrt{144} = \sqrt{s^2}

12 = s

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Use slopes to determine if the lines y= -x/3- 9 and 6x – 2y = -5 are perpendicular.
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They are perpendicular.

Step-by-step explanation:

When we convert the equation 6x-2y=-5 into y=mx+b form, it changes into y=3x-5/2. Since we know that perpendicular slopes are opposite reciprocal, the opposite reciprocal of -x/3 is 3. So, we know that these 2 slopes are perpendicular.

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4 years ago
A quadrilateral has angles that measure 115, 97, and 68. What is the measure of the missing angle? Plz help me I don't know the
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Answer:

Step-by-step explanation:

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8 0
3 years ago
Read 2 more answers
Learning Task 1 4/625 11. 796 A. Simplify the radical expressions 1. V63 6. V24 2. 48 7. 781 3. 775 8. V128 4. 99 9. 340 5. 92 1
kompoz [17]

Question:

Simplify the radical expressions

1.\ \sqrt{63     2.\ \sqrt{48    3.\ \sqrt{75      4.\ \sqrt{99      5.\ \sqrt{92

6.\ \sqrt[3]{24}      7.\ \sqrt[3]{81}      8.\ \sqrt{128}     9.\sqrt[3]{40}     10.\ \sqrt[3]{135}

Answer:

\sqrt{63}= 3 \sqrt7

\sqrt{48} = 4\sqrt{3}

\sqrt{75} = 5\sqrt{3}

\sqrt{99} = 3 \sqrt{11

\sqrt{92} = 2\sqrt{23

\sqrt[3]{24} = 2 \sqrt[3]{3}

\sqrt[3]{81} =3\sqrt[3]{3}

\sqrt{128} = 8 \sqrt{2}

\sqrt[3]{40} = 2 \sqrt[3]{5}

\sqrt[3]{135} =3\sqrt[3]{5}

Step-by-step explanation:

1.\ \sqrt{63    

Express 63 as 9 * 7

\sqrt{63}= \sqrt{9 * 7

Split:

\sqrt{63}= \sqrt{9} * \sqrt7

\sqrt{63}= 3 * \sqrt7

\sqrt{63}= 3 \sqrt7

2.\ \sqrt{48    

Express 48 as 16 * 3

\sqrt{48} = \sqrt{16*3}

Split

\sqrt{48} = \sqrt{16}*\sqrt{3}

\sqrt{48} = 4*\sqrt{3}

\sqrt{48} = 4\sqrt{3}

3.\ \sqrt{75    

Express 75 as 25 * 3

\sqrt{75} = \sqrt{25*3}

Split

\sqrt{75} = \sqrt{25}*\sqrt{3}

\sqrt{75} = 5\sqrt{3}

4.\ \sqrt{99  

Express 99 as 9 * 11

\sqrt{99} = \sqrt{9} * \sqrt{11}

Split

\sqrt{99} = 3 \sqrt{11

5.\ \sqrt{92

Express 92 as 4 * 23

\sqrt{92} = \sqrt{4} * \sqrt{23

\sqrt{92} = 2* \sqrt{23

\sqrt{92} = 2\sqrt{23

6.\ \sqrt[3]{24}    

Express 24 as 8 * 3

\sqrt[3]{24} = \sqrt[3]{8} * \sqrt[3]{3}

Express 8 as 2^3

\sqrt[3]{24} = \sqrt[3]{2^3} * \sqrt[3]{3}

\sqrt[3]{24} = 2 \sqrt[3]{3}

7.\ \sqrt[3]{81}

Express 81 as 27 * 3

\sqrt[3]{81} =\sqrt[3]{27}*\sqrt[3]{3}

Express 27 as 3^3

\sqrt[3]{81} =\sqrt[3]{3^3}*\sqrt[3]{3}

\sqrt[3]{81} =3\sqrt[3]{3}

8.\ \sqrt{128}    

Express 128 as 64 * 2

\sqrt{128} = \sqrt{64} * \sqrt{2}

\sqrt{128} = 8 \sqrt{2}

9.\sqrt[3]{40}

Express 40 as 8 * 5

\sqrt[3]{40} = \sqrt[3]{8} * \sqrt[3]{5}

\sqrt[3]{40} = \sqrt[3]{2^3} * \sqrt[3]{5}

\sqrt[3]{40} = 2 \sqrt[3]{5}

10.\ \sqrt[3]{135}

Express 135 as 27 * 5

\sqrt[3]{135} =\sqrt[3]{27}*\sqrt[3]{5}

Express 27 as 3^3

\sqrt[3]{135} =\sqrt[3]{27}*\sqrt[3]{5}

\sqrt[3]{135} =3\sqrt[3]{5}

4 0
3 years ago
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