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3 years ago

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Chemistry

2 answers:

Rus_ich [418]3 years ago

4 0

Answer:

$not \: inrested$

Explanation:

$thnxx \: for \: \\ pts$

jekas [21]3 years ago

4 0

Naaaaa, ima take da points and leave, u do ur thing

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Draw the major 1,2- and 1,4-addition products that form as a result of the following reaction between one equivalent each of 2,4

lapo4ka [179]

The major 1,2- and 1,4-addition products are 4-Bromo-2-hexene and 2-Bromo-2-hexene.

What is Markovnikov Rule ?

Markovnikov rule explains that in addition reaction of alkene react with a hydrogen halide. The hydrogen atom is attached to the carbon atom that is already bonded to the greatest number of hydrogen.

<h3>What is Addition Reaction ?</h3>

An addition reaction is an organic reaction occur when two or more molecules combine to form a larger molecule without the loss of any atoms present in reactant.

Thus from the above conclusion we can say that The major 1,2- and 1,4-addition products are 4-Bromo-2-hexene and 2-Bromo-2-hexene.

Learn more about the Markovnikov Rule here: brainly.com/question/21496002

#SPJ1

6 0

2 years ago

1. The H atom and the Be +3 ion each have one electron. Does the Bohr model predict their spectra accurately? Would you expect t

lesantik [10]

Answer:

yes the Bohr model predicts their spectra accurately

Explanation:

The Bohr model based on one electron system

The atom H has a single atom and the ion Be+3 has a single atom as well and this proves that the Bohr model predicts their spectra accurately .

also apply the equation model to further explain

E = $\frac{-(z^2) (2.18 * 10^{-18}j) }{n^2}$

z = atomic number

for H the value of z = 1

for Be+3 the value of z = 4

when this values are substituted into the equation above

E = $\frac{-(1) (2.18 * 10^{-18}j) }{n^2}$ , E = $\frac{-(4) (2.18 * 10^{-18}j) }{n^2}$

this results show that the energy level of Be+3 is higher than the energy level of H by a factor of 16 , and this shows that their line patterns are similar

6 0

3 years ago

Fill in the blank: after Mitosis, each daughter cell has identical

galina1969 [7]

Genes
when mitosis occurs it creates an exact copy of itself

7 0

3 years ago

Notice that "SO4" appears in two different places in this chemical equation. SO 2−4 is a polyatomic ion called "sulfate." What n

kramer

3CaCl₂ + Al₂(SO₄)₃ = 3CaSO₄↓ + 2AlCl₃

8 0

3 years ago

Which solute would be more effective at lowering the freezing point of water: MgCl2 and KNO3? Explain.

Phantasy [73]

Answer:

AlCl₃.

Explanation:

Adding solute to water causes depression of the boiling point.

The depression in freezing point (ΔTf) can be calculated using the relation:

ΔTf = i.Kf.m,

where, ΔTf is the depression in freezing point.

i is the van 't Hoff factor.

van 't Hoff factor is the ratio between the actual concentration of particles produced when the substance is dissolved and the concentration of a substance as calculated from its mass. For most non-electrolytes dissolved in water, the van 't Hoff factor is essentially 1.

Kf is the molal depression constant of water.

m is the molality of the solution (m = 1.0 m, for all solutions).

(1) NaCl:

i for NaCl = no. of particles produced when the substance is dissolved/no. of original particle = 2/1 = 2.

∴ ΔTb for (NaCl) = i.Kb.m = (2)(Kf)(1.0 m) = 2(Kf).

(2) MgCl₂:

i for MgCl₂ = no. of particles produced when the substance is dissolved/no. of original particle = 3/1 = 3.

∴ ΔTb for (MgCl₂) = i.Kb.m = (3)(Kf)(1.0 m) = 3(Kf).

(3) NaCl:

i for KBr = no. of particles produced when the substance is dissolved/no. of original particle = 2/1 = 2.

∴ ΔTb for (KBr) = i.Kb.m = (2)(Kf)(1.0 m) = 2(Kf).

(4) AlCl₃:

i for AlCl₃ = no. of particles produced when the substance is dissolved/no. of original particle = 4/1 = 4.

∴ ΔTb for (CoCl₃) = i.Kb.m = (4)(Kf)(1.0 m) = 4(Kf).

So, the ionic compound will lower the freezing point the most is: AlCl₃

4 0

3 years ago

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