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Ber [7]
3 years ago
9

Starting from a 1 M stock of NaCl, how will you make 50 ml of 0.15 M NaCl?

Chemistry
1 answer:
WARRIOR [948]3 years ago
6 0

Answer:

We need 7.5 mL of the 1M stock of NaCl

Explanation:

Data given:

Stock = 1M this means 1 mol/ L

A 0.15 M solution of 50 mL has 0.0075 moles NaCl per 50 mL

Step 2: Calculate the volume of stock we need

The moles of solute will be constant

and n = M*V  

M1*V1 = M2*V2

⇒ with M1 = the initial molair concentration = 1M

⇒ with V1 = the volume we need of the stock

⇒ with V2 = the volume we want to make of the new solution = 50 mL = 0.05 L

⇒ with M2 = the concentration of the new solution = 0.15 M

1*V1 = 0.15*(50)

V1 = 7.5 mL

Since 0.0075 L of 1M solution contains 0.0075 moles

50 mL solution will contain also 0.0075 moles but will have a molair concentration of 0.0075 moles / 0.05 L =0.15 M

We need 7.5 mL of the 1M stock of NaCl

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Answer:

Wouldn't rust because zinc will lose electrons more readily than iron and will therefore oxidize first.

Explanation:

This process whereby rusting of steel is prevented by coating the steel with a layer of zinc is known as galvanization.

Now, in this process, the steel object will be coated in a thin layer of zinc. This coating will prevent oxygen and water from reaching the underneath metal since the zinc will also act as a sacrificial metal.

Now, Zinc is used because it has a lower reduction potential than iron and thus it will get easily more oxidized than iron. Which means the zinc will lose electrons more readily than iron.

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7 0
3 years ago
1Explain why the ions of sodium, magnesium and aluminium are smaller than their corresponding atoms.
ella [17]

Answer:

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Hope this helps!

Explanation:

3 0
3 years ago
What change would increase the amount of solid solute able to be dissolved in liquid water?
exis [7]
Bonjour,

increasing temperature.
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3 0
3 years ago
In a chemical reaction, the __________ is consumed completely during the reaction. A) stoichiometry B) excess reagent C) ideal c
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7 0
3 years ago
A 0.75mol calcium carbonate (CaCO3) pellet has what mass?
aleksandr82 [10.1K]

Answer:

75 g  

Step-by-step explanation:

<em>Step 1. </em>Calculate the molar mass of CaCO₃

Ca                    =   40.08

  C                    =   12.01

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3 years ago
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