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kirill [66]
3 years ago
15

5.00 ml of commercial bleach was diluted to 100.0 ml. 25.0 ml of the diluted sample was titrated with 4.56 ml of 0.100 m s2o3 2-

. what is the concentration of hypochlorite in the original bleach solution? assume the density of the commercial bleach is 1.08 g/ml. calculate the average percent by mass of naclo in the commercial bleach.
Chemistry
1 answer:
aev [14]3 years ago
3 0

The solution would be like this for this specific problem:

 

4 NaOCl + S2O3{2-} + 2 OH{-} → 2 SO4{2-} + H2O + 4 NaCl

<span>(0.00456 L) x (0.100 mol/L S2O3{2-}) x (4 mol NaOCl / 1 mol S2O3{2-}) x (100.0 mL / 25 mL) x </span><span>
<span>(74.4422 g NaClO/mol) = 0.54313 g </span></span>

<span>(5.00 mL) x (1.08 g/mL) = 5.40 g solution </span>

(0.54313 g) / (5.40 g) = 0.101 = 10.1%

 

So, the average percent by mass of NaClO in the commercial bleach is 10.1%.

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The answer to your question is 33.4 ml

Explanation:

Data

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Process

1.- Convert celsius to kelvin

T1 = 20 + 273 = 293°K

T2 = -60 + 273 = 233°K

2.- Use the Charles' law to solve this problem

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                V2 = \frac{V1T2}{T1}

3.- Substitution

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4.- Simplification

                V2 = \frac{9786}{293}

5.- Result

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